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At STP water vapor will behave as an ideal gas so the volume can be found by rearranging the ideal gas law to solve for volume:

PV = nRT => V = nRT/P

IUPAC defines STP as:

P = 100 kPa (14.504 psi, 0.986 atm)

T = 273.15 K (0 °C, 32 °F)

and

R = 8.31447 kPa·liter/gmole/K

n = 150 g water/(18.01528 g water/gmole water) = 8.33 gmol water

So

V = 189 liters

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Q: What volume is occupied by 150g of water vapor at STP?
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