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Molecular weight of propene, C3H6 is 42.08.
Assuming all C goes to CO2 (rather than CO), reaction is 2C3H6 + 9O2 = 6CO2 + 6H2O
Molecular weight of O2 is 32.
So
(2x42.08)g of propene would react with (9x32)g of O2
So ratio is 84.16 to 377.77
So 30g of propene reacts with 30/84.16 x 377.77=134.66g of O2
You then need to know that 1mol of an ideal gas occupies 22.4 litres at standard temperature and pressure, so
134.66 / 32 occupies = 94.262 litre
What else can I help you with?
Assuming no change in temperature and pressure calculate the volume of O2 in liters required for the complete combustion of 14.9 L of butane C4H10?
The balanced chemical equation for the combustion of butane is: 2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O. This means it requires 13 moles of O₂ for every 2 moles of butane. The volume of O₂ needed would be (14.9 L * 13 mol) / 2 = 96.85 L of O₂.
If 50 l of gaseous CH4 is burned at STP what volume of 02 is required for complete combustion and what volume of CO2 is produced?
For complete combustion of 50 L of gaseous CH4 at STP, you would need 100 L of O2 (in a 1:2 ratio). This is based on the balanced chemical equation: CH4 + 2O2 -> CO2 + 2H2O. The volume of CO2 produced would also be 100 L, as this is also based on the stoichiometry of the chemical reaction.
What is the volume of oxygen required for complete combustion of 0.5 liter of H2S at stp?
For gases it is valid that the Volume ratio of reactants and products is the same as the mole ratio (in the balanced equation) when pressure and Temperature are kept coonstant. This is according to the general gas law (Boyle-Gay-Lussac): p.V = m.R.T2H2S + 3O2 --> 2H2O + 2SO2so 0.5 L H2S needs 0.5 * [3/2] = 0.75 L O2
Minimum volume of urine required for cs?
The minimum volume of urine required for a complete urine analysis (urinalysis) is typically 10-15 mL. This amount is needed to perform the various tests to assess the physical, chemical, and microscopic properties of the urine sample. A larger volume may be required for additional tests or specific investigations.
What is the mass of air required for the complete combustion of 1g of methane?
CH4 + 2 O2 --> CO2 + 2 H2Ox / 64 = 1 / 16x = 4 g oxygenAssuming oxygen is 20% oxygen...4 = .2 xx = 20 g air that is one possible answer.A better answer--- air is 20% oxygen by volume and 80% nitrogen by volume.1g methane / 16 = 0.0625 mole0.0625 / 1mole meth = x / 2mole oxyx = 0.125 mole oxygen =20% of air--- 0.625 mole 'air'0.2 x 32 + 0.8 x 28 = 28.8 g/mole of air0.625 x 28.8 = 18 grams of airSince air is 20% oxygen by volume, the 2nd answer is best.
Assuming no change in temperature and pressure calculate the volume of O2 in liters required for the complete combustion of 14.9 L of butane C4H10?
The balanced chemical equation for the combustion of butane is: 2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O. This means it requires 13 moles of O₂ for every 2 moles of butane. The volume of O₂ needed would be (14.9 L * 13 mol) / 2 = 96.85 L of O₂.
What volume of oxygen is required for the complete combustion of a mixture of 5 cm of CH and 5 cm of C H?
The question is impossible to answer.You cannot have 5 cm of CH or C H. You need a volume, not a length.The second substance listed is the same as the first, but with a space.
What are the total air volume supply requirements for an atmospheric burner?
The total air volume supply requirements for an atmospheric burner depend on factors such as the burner size, fuel type, and combustion efficiency. Typically, air volume is calculated based on the stoichiometric air-to-fuel ratio required for complete combustion. It is important to ensure that the correct amount of air is supplied to achieve optimal combustion and prevent issues such as inefficient burning or production of harmful emissions.
If 50 l of gaseous CH4 is burned at STP what volume of 02 is required for complete combustion and what volume of CO2 is produced?
For complete combustion of 50 L of gaseous CH4 at STP, you would need 100 L of O2 (in a 1:2 ratio). This is based on the balanced chemical equation: CH4 + 2O2 -> CO2 + 2H2O. The volume of CO2 produced would also be 100 L, as this is also based on the stoichiometry of the chemical reaction.
What is the volume of oxygen required for complete combustion of 0.5 liter of H2S at stp?
For gases it is valid that the Volume ratio of reactants and products is the same as the mole ratio (in the balanced equation) when pressure and Temperature are kept coonstant. This is according to the general gas law (Boyle-Gay-Lussac): p.V = m.R.T2H2S + 3O2 --> 2H2O + 2SO2so 0.5 L H2S needs 0.5 * [3/2] = 0.75 L O2
Compression ratio of the internal combustion engine is defined as?
The compression ratio of an internal-combustion engine, or an IC engine as it is more commonly called, is the ratio of the volume the highest capacity of the combustion chamber to its lowest capacity. In the IC engine, the piston makes a stroke, resulting in the compression of the air in the combustion chamber - the ratio between the volume of the cylinder and combustion chamber when the piston is at the bottom of its stroke, and the volume of the combustion chamber when the piston is at the top of its stroke, is the compression ratio.
What makes incomplete combustion more dangerous than complete combustion?
Incomplete combustion involves the generation of carbon monoxide in addition to carbon dioxide and water generated in complete combustion. Carbon monoxide is highly toxic. While carbon dioxide is produced by the body itself and can only kill if at a very high concentration (7% to 10% of air by volume) or by depriving the victim of oxygen for prolonged periods of time, carbon monoxide is not a physiological gas and can kill at low concentrations (0.32% of air by volume) and in a relatively short amount of time (less than 30 minutes). The toxicity of carbon monoxide is believed to be involved in compromising the ability of hemoglobin and myoglobin to transfer and store oxygen and disabling cellular respiration through blocking cytochrome oxidase.
What is cutoff ratio?
Cutoff ratio is not the ratio of the volume of the cylinder at the end of combustion to the start of the combustion process in a diesel engine. actually cutoff ratio means point at which fuel injected for a period and fuel delivery is stopped at required instant -is called cutoff ratio.............
What does chamber volume mean in a engine?
The chamber volume refers to the compression ratio of the external combustion of the engine.
When was Complete History Volume One created?
Complete History Volume One was created in 1982.
How does the stroke increase the force of the combustion?
In a stroke engine, the stroke increases the force of combustion by creating a larger volume in which the air and fuel mixture can burn. This larger volume allows for greater expansion of the gases during combustion, which results in increased pressure and force exerted on the piston.
What will be the volume of NO formed during the combustion of 1000 liters of NH3?
The volume of NO is 1011.07 L; the reaction is possible only with a catalyst.
