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What volume will 2.00 moles of hydrogen gas occupy at 2.62 ATM of pressure and 300.C?
Wiki User
∙ 8y ago
PV = nRT
V = nRT/P = (2.00 mol)(0.08206 Latm/kmol)(573K)/(2.62 atm)
V = 35.9 liters (to 3 sig. figs.)
Wiki User
∙ 8y ago
Wiki User
∙ 8y agoThe volume is 35,9 L.
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