Copper will "plate" on to the outside of the nail. The observer will see a copper colored material on the nail that looks almost like rust when dry.
Fe + CuSO4 → FeSO4 + Cu
Copper precipitates onto the nail.
When an iron nail is placed in a copper sulfate solution, a single displacement reaction occurs. The iron will displace the copper in the solution, forming iron sulfate and depositing copper on the nail, causing it to turn a brownish color due to the presence of copper.
If you add iron to a solution of magnesium sulfate, a displacement reaction would occur, where the iron would displace the magnesium in the sulfate compound. This would result in the formation of iron sulfate and magnesium metal.
When copper sulfate is added to iron, a chemical reaction takes place where the copper in the copper sulfate replaces the iron to form copper metal and iron sulfate. This reaction can be represented by the equation: CuSO4 + Fe → FeSO4 + Cu.
The product of iron sulfate reacting with calcium carbonate is iron carbonate and calcium sulfate. The iron from the iron sulfate displaces the calcium in the calcium carbonate to form iron carbonate, while the sulfate from the iron sulfate combines with the calcium to form calcium sulfate.
Since iron is a more active metal than copper, the iron would replace the copper in the copper sulfate, forming iron sulfate, and releasing elemental copper. The copper will not shape itself into a copper vessel, so eventually, the iron sulfate would leak out of the iron vessel, and eventually, if there is enough copper sulfate, the iron vessel will cease to exist.
Copper is displaced by iron and deposited on the nail.
This reaction is: Fe(s) + CuSO4(aq)----- --> FeSO4(aq) + Cu(s)
When an iron nail is placed in a copper sulfate solution, a single displacement reaction occurs. The iron will displace the copper in the solution, forming iron sulfate and depositing copper on the nail, causing it to turn a brownish color due to the presence of copper.
If you add iron to a solution of magnesium sulfate, a displacement reaction would occur, where the iron would displace the magnesium in the sulfate compound. This would result in the formation of iron sulfate and magnesium metal.
When copper sulfate is added to iron, a chemical reaction takes place where the copper in the copper sulfate replaces the iron to form copper metal and iron sulfate. This reaction can be represented by the equation: CuSO4 + Fe → FeSO4 + Cu.
Iron (II) sulfate is the correct name for this compound. The Fe ion has a charge of 2 and so does the sulfate ion, so there is no subscript after them.
The product of iron sulfate reacting with calcium carbonate is iron carbonate and calcium sulfate. The iron from the iron sulfate displaces the calcium in the calcium carbonate to form iron carbonate, while the sulfate from the iron sulfate combines with the calcium to form calcium sulfate.
Since iron is a more active metal than copper, the iron would replace the copper in the copper sulfate, forming iron sulfate, and releasing elemental copper. The copper will not shape itself into a copper vessel, so eventually, the iron sulfate would leak out of the iron vessel, and eventually, if there is enough copper sulfate, the iron vessel will cease to exist.
Iron sulfate can be prepared by dissolving iron oxide or iron metal in sulfuric acid. The reaction produces iron sulfate and water. The solution can then be evaporated to obtain solid iron sulfate.
Iron (II) sulfate has iron in the +2 oxidation state, while iron (III) sulfate has iron in the +3 oxidation state. This means iron (II) sulfate has a lower charge on the iron ion compared to iron (III) sulfate, which affects its chemical properties and reactivity.
Sulfur, oxygen atoms and a whole lotta love
Actually, nothing will happen. This is because iron is much less reactive than zinc, which means it is unable to displace the zinc from the sulfate solution. If you were to do the reverse, the zinc would displace the iron in the iron sulfate solution to get zinc sulfate and Iron.