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What would be the percent yield of the reaction be if the theoretical yield is 11.22 g but the actual yield was 8.67 g?
Wiki User
∙ 8y ago
In this case the yield is 77,27 %.
Wiki User
∙ 8y ago
lenpollock
8.67 x 100 / 11.22 = 77.27...%
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Would the percent yield be different if the actual yield and theoretical yield were in units of moles?
Not at all. Just be consistent with the units of both actual and theoretical yield.
Would the experimental percent oxygen be higher or lower than the theoretical percent oxygen?
because of variable in the situation '
Why is the actual yield less than the theoretical yield?
All reactants have impurities and those impurities become the limiting factor for the reaction. This means that the actual yield will be lower because there will not be the total measured amount of reactants. Fewer reactants equals lower output.
Distinguish between ideal and real stoichiometric calculations?
The theoretical yield of a reaction is the amount of some product, usually given in mass units of grams, that you would expect to get if the reaction based on a stoichiometric calculation not actually "running" the reaction in the laboratory. The actual yield is just that,it is the actual amount of product, in grams you actually produced after really running the experiment in the lab.Actual yield data comes from experimentally determined results. You can not "calculate" it.
Why is it important to determine the percent recovery of chemical reactions?
If the rate of reaction is too fast it can not be controlled. From a Health and Safety point of view this is dangerous. If the rate can be controlled by cooling for example, this would require adequate water (or other coolant ) control/flow. This would have to be taken into consideration at the plant design stage. This could involve a lot of extra cost. If the rate of reaction is too slow this could affect the whole process economics.
Would the percent yield be different if the actual yield and theoretical yield were in units of moles?
Not at all. Just be consistent with the units of both actual and theoretical yield.
Would the experimental percent oxygen be higher or lower than the theoretical percent oxygen?
because of variable in the situation '
Actual mechanical advantage is always better then theoretical MA why?
"Better" is an interesting word. I would guess that theoretical MA beats actual MA any day of the week. Some energy is lost in friction.
Why is the actual yield less than the theoretical yield?
All reactants have impurities and those impurities become the limiting factor for the reaction. This means that the actual yield will be lower because there will not be the total measured amount of reactants. Fewer reactants equals lower output.
What does the percent yield of a reaction measure?
It measures the amount of reactants actually produced in a reaction compared to the amount that would theoretically be produced if 100% of the reactants were converted to products according to the stoichiometry of the reaction. It is found by: actual moles of products ÷ predicted moles of products * 100%
What if a potassium chlorate sample is contaminated with KCL would the experimental percent oxygen be higher or lower than the theoretical percent oxygen?
the experimental % oxygen would be lower because there would be more KCL in the simple than oxygen
Why is theoretical yield almost never?
This is not true, experimental yield is can be higher than theoretical or equal theoretical yield. If the experimental yield is greater though, that means that something went wrong in the experiment and that was most likely a contaminant. Ideally, you want to be as close to the theoretical yield as possible.
How many miles is Washington to Manila Philippines?
The shortest 'theoretical' air distance from Washington DC, USA to Manila, Philippines is 8572 miles. Actual distance would depend on airport location and actual route of the flight.
What would decrease the value determined for an actual yield of product?
a competing reaction that led to product decomposition
How many times would a coin have to show heads in 50 tosses to show an experimental probability of 20 percent more than the theoretical probability of getting heads?
Theoretical probability = 0.5 Experimental probability = 20% more = 0.6 In 50 tosses, that would imply 30 heads.
What does it mean if you get a negative number when you calculate for percent error?
Depending on whether you subtract actual value from expected value or other way around, a positive or negative percent error, will tell you on which side of the expected value that your actual value is. For example, suppose your expected value is 24, and your actual value is 24.3 then if you do the following calculation to figure percent error:[percent error] = (actual value - expected value)/(actual value) - 1 --> then convert to percent.So you have (24.3 - 24)/24 -1 = .0125 --> 1.25%, which tells me the actual is higher than the expected. If instead, you subtracted the actual from the expected, then you would get a negative 1.25%, but your actual is still greater than the expected. My preference is to subtract the expected from the actual. That way a positive error tells you the actual is greater than expected, and a negative percent error tells you that the actual is less than the expected.
Would it be engage in resume puffing and then disclose the actual facts in an interview?
Yes, it would be wrong to engage in resume puffing. The actual facts in an interview are that · Eleven percent of all applicants lied about their reasons for leaving a previous job. · Four percent fudged job titles on their resumes
