Mg 2+
This cation has already donated it's valence shell and would require that core electrons be pulled by a large ionization energy.
It would take less energy to remove an electron from sodium than from chlorine because sodium has a lower ionization energy than chlorine. This means that sodium's outer electron is held less tightly compared to chlorine's outer electron.
It would be most difficult to remove an electron from chlorine because it has the highest electron affinity among the elements mentioned. Sodium has the lowest ionization energy, meaning it's easiest to remove an electron from it.
Yes, argon can form ions, but it is less likely to do so because it is a noble gas with a full outer electron shell, making it stable and unreactive. It would require a significant amount of energy to remove an electron from argon to form an ion.
Helium would be the element that fits this description. It has a high ionization energy, meaning it requires a lot of energy to remove an electron, and tends to be chemically inactive because its outer electron shell is full.
It would be harder to remove an electron from chlorine because it has a higher electronegativity compared to sodium. This means that chlorine has a stronger pull on its electrons, making it more difficult to remove an electron.
This is an electron situated on the outermost level.
The electron would be removed from the outermost energy level, which is the fourth energy level, for calcium.
It would take less energy to remove an electron from sodium than from chlorine because sodium has a lower ionization energy than chlorine. This means that sodium's outer electron is held less tightly compared to chlorine's outer electron.
Core electrons. Probably the 1s level would require the most ionization energy to pull these electrons.
It would be most difficult to remove an electron from chlorine because it has the highest electron affinity among the elements mentioned. Sodium has the lowest ionization energy, meaning it's easiest to remove an electron from it.
Yes, argon can form ions, but it is less likely to do so because it is a noble gas with a full outer electron shell, making it stable and unreactive. It would require a significant amount of energy to remove an electron from argon to form an ion.
n=1to n=2
Selenium does not have a second electron affinity because adding an additional electron to selenium would require more energy to overcome the repulsion between the negatively charged electron and the negatively charged selenium ion. In other words, the energy required to add a second electron to selenium is higher than the energy released in the process.
yes, the potato would be the hgh energy electron
Helium would be the element that fits this description. It has a high ionization energy, meaning it requires a lot of energy to remove an electron, and tends to be chemically inactive because its outer electron shell is full.
Electrons are attracted to the positive charge on the nucleus. The further an electron is found from the nucleus of an atom, the lower the force of attraction between it and the nucleus. Therefore an electron far away from the nucleus (like a valence electron) will have less of an attraction to the nucleus than one close to it. A lower attraction to the nucleus translates into the fact that less energy would then be required to remove the electron from the vicinity of that nucleus.
To calculate the energy it takes to remove a single electron from an atom on the surface of solid rubidium (Rb), you need to divide the given energy by Avogadro's number since 1 mole contains Avogadro's number of particles (6.022 x 10^23). Therefore, the energy to remove a single electron from an atom on the surface of solid rubidium would be 208.4 kJ divided by Avogadro's number.