usually it will be copper sulfate as a limiting reagent
To determine the limiting reactant, we need to compare the moles of each reactant. First, calculate the moles of aluminum and copper sulfate separately. Then, determine the mole ratio between them and see which reactant is present in lower amount compared to the stoichiometric ratio. The reactant that is present in lower moles is the limiting reactant.
The balanced chemical equation for the reaction is: Hg(NO₃)₂ + Na₂SO₄ → HgSO₄ + 2NaNO₃ From the given amounts, the limiting reagent is sodium sulfate. The amount of mercury(II) sulfate formed can be calculated using stoichiometry and the molar masses of the compounds.
The word equation for aluminum sulfate is: aluminum sulfate + water → aluminum hydroxide + sulfuric acid.
In aluminum sulfate, the molar mass of aluminum is 27 g/mol. Calculate the amount of aluminum in 5.60 g of aluminum sulfate using the molar ratio between aluminum and aluminum sulfate (1:1). Therefore, there are 5.60 grams of aluminum in 5.60 grams of aluminum sulfate.
Yes, aluminum sulfate is soluble in water.
To determine the limiting reactant, we need to compare the moles of each reactant. First, calculate the moles of aluminum and copper sulfate separately. Then, determine the mole ratio between them and see which reactant is present in lower amount compared to the stoichiometric ratio. The reactant that is present in lower moles is the limiting reactant.
When barium sulfate is made, the limiting reagent is the one that is completely consumed in the reaction and determines the amount of product formed. In this case, if barium ions (Ba2+) and sulfate ions (SO42−) are the reactants, the limiting reagent would be the one that is present in lower molar quantity. The one in excess would be the one that is present in higher molar quantity. Without the quantities of each ion provided, it is difficult to determine which is the limiting reagent and which is in excess.
The balanced chemical equation for the reaction is: Hg(NO₃)₂ + Na₂SO₄ → HgSO₄ + 2NaNO₃ From the given amounts, the limiting reagent is sodium sulfate. The amount of mercury(II) sulfate formed can be calculated using stoichiometry and the molar masses of the compounds.
The word equation for aluminum sulfate is: aluminum sulfate + water → aluminum hydroxide + sulfuric acid.
In aluminum sulfate, the molar mass of aluminum is 27 g/mol. Calculate the amount of aluminum in 5.60 g of aluminum sulfate using the molar ratio between aluminum and aluminum sulfate (1:1). Therefore, there are 5.60 grams of aluminum in 5.60 grams of aluminum sulfate.
the percentage composition of aluminum sulfate is 342
Yes, aluminum sulfate is soluble in water.
No, sodium sulfate does not react with aluminum. Sodium sulfate is a neutral salt and does not possess the capability to corrode or react with aluminum metal.
To combine aluminum sulfate, simply mix the required amount of aluminum sulfate powder with water in a container. Stir the mixture until the powder is fully dissolved. The aluminum sulfate solution is now ready for use.
Aluminum Sulfide ==> Al2S3 Aluminum Sulfate ==> Al2(SO4)3 Aluminum sulfide is just aluminum and sulfur, while aluminum sulfate is Aluminum plus Sulfate (Polyatomic ion made of sulfur and oxygen)
To find the mass of 0.25 moles of aluminum sulfate, you need to know the molar mass of aluminum sulfate. The molar mass of aluminum sulfate (Al2(SO4)3) is approximately 342.15 g/mol. Therefore, the mass of 0.25 moles of aluminum sulfate would be around 85.54 grams.
When Epsom salt (magnesium sulfate) is mixed with aluminum sulfate, a double displacement reaction occurs. The magnesium ions from Epsom salt switch places with the aluminum ions from aluminum sulfate, forming magnesium sulfate and aluminum hydroxide. This reaction results in a white precipitate of aluminum hydroxide forming in the solution, while magnesium sulfate remains dissolved.