The products are Potassium bromide(KBr), Water(H2O) and Carbon(CO2).
KHCO3 + HBr ----> KBr + H2O + CO2
Yes: reactions with HBr, HI, H2S, H2Se, H2Te
The reaction is:Cd + 2 HBr = CdBr2 + H2
CH4 + Br2 = CH3Br + HBr
Bromine reacts with water to form a mixture of Hydrobromic Acid, HBr, and Hypobromous Acid, HBrO.
FeBr2 + H3PO4 <--> Fe3(PO4)2 + HBr
Potassium bicarbonate (KHCO3) and hydrobromic acid (HBr) will react to form potassium bromide (KBr), water (H2O), and carbon dioxide (CO2). Here's the balanced equation:KHCO3 + HBr --> KBr + H2O + CO2(A closer look actually tells you that the other product besides potassium bromide is carbonic acid, H2CO3; but under normal conditions, that quickly decomposes into water and carbon dioxide, so the above equation actually reflects two different reactions: one double replacement and one decomposition.)
Bromomethane CHBr3 and Hydrogen Bromide HBr
Yes: reactions with HBr, HI, H2S, H2Se, H2Te
HBR doesn't react with Propane, but it does with Propene. The product is either 1-bromo propane(minor product) or 2-bromo propane(major product). To determine which product will be the major product, use the Markovnikov's rule.
The reaction is:Cd + 2 HBr = CdBr2 + H2
KF+HBr---->HF+KBr
CH4 + Br2 = CH3Br + HBr
Bromine reacts with water to form a mixture of Hydrobromic Acid, HBr, and Hypobromous Acid, HBrO.
The compound CH2=CH-CH=CH2 when reacts with HBr gives 1,4 addition product, CH3-CH=CH-CH2Br
Khco3+h2o
FeBr2 + H3PO4 <--> Fe3(PO4)2 + HBr
The chemical reaction is:2 HI + Br2 = 2 HBr + I2