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When a sample of neon with a volume of 648 mL and a pressure of 0.985 ATM was heated from 16.0 to 63.0 C its volume became 689 mL What was its final pressure in ATM?
Wiki User
∙ 12y ago
Begin with the Equation; P1V1/ T1 = P2V2/ T2
Therefore, (785 torr)(2.00 L) / (37.0 C) = (X)(3.24 L)/ (58.0 C) = 759.59 TORR.
To get the answer into ATM, you need to divide the answer in torr by 760.
EX. 760torr = 1 atm.
759.59 torr / 760 torr = .999 atm.
Wiki User
∙ 14y ago
Wiki User
∙ 12y ago1.08 ATM
Wiley plus? lol
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