yes, it would occur because iron is more reactive than copper (look at an activity series to see this). metals trade places in a single replacement reaction if the metal that is alone on the reactact side of the equation has a higher reactivity than the metal attached to the nonmetal.
It doesnt seem like you were answering THIS question??
The products of this single replacement reaction are iron(II) nitrate and copper. The iron displaces the copper in the reaction, resulting in the formation of iron(II) nitrate and elemental copper.
The reaction between iron and copper nitrate in a single replacement reaction would produce iron(II) nitrate and copper metal. The iron would replace the copper in the nitrate compound, resulting in the formation of iron(II) nitrate and copper metal as products.
The products of the reaction between iron and copper(II) nitrate are iron(II) nitrate and copper metal. Iron displaces copper in the compound because it is more reactive, leading to the formation of iron(II) nitrate and copper.
The formula for iron reacting with copper(II) nitrate is: Fe + Cu(NO3)2 -> Fe(NO3)2 + Cu. This is a single displacement reaction where iron displaces copper from copper nitrate to form iron(II) nitrate and copper metal.
The iron will replace the copper in the copper(II) nitrate solution, forming iron(II) nitrate and copper metal as products. The balanced chemical equation for the reaction is: Fe + Cu(NO3)2 -> Fe(NO3)2 + Cu.
The products of this single replacement reaction are iron(II) nitrate and copper. The iron displaces the copper in the reaction, resulting in the formation of iron(II) nitrate and elemental copper.
The reaction between iron and copper nitrate in a single replacement reaction would produce iron(II) nitrate and copper metal. The iron would replace the copper in the nitrate compound, resulting in the formation of iron(II) nitrate and copper metal as products.
The products of the reaction between iron and copper(II) nitrate are iron(II) nitrate and copper metal. Iron displaces copper in the compound because it is more reactive, leading to the formation of iron(II) nitrate and copper.
The formula for iron reacting with copper(II) nitrate is: Fe + Cu(NO3)2 -> Fe(NO3)2 + Cu. This is a single displacement reaction where iron displaces copper from copper nitrate to form iron(II) nitrate and copper metal.
When copper reacts with silver nitrate, there is a displacement reaction where the copper displaces silver from the silver nitrate solution. This results in the formation of copper(II) nitrate solution and solid silver. The reaction is a single displacement reaction where copper is more reactive than silver.
The formula for aqueous copper nitrate is Cu(NO3)2.
The iron will replace the copper in the copper(II) nitrate solution, forming iron(II) nitrate and copper metal as products. The balanced chemical equation for the reaction is: Fe + Cu(NO3)2 -> Fe(NO3)2 + Cu.
A displacement reaction, in which the copper dissolves to form copper nitrate and replaces silver ions in the original silver nitrate, reducing the silver ions to metallic silver.
The chemical formula for copper (I) nitrate is CuNO3.
A single displacement reaction would occur, with copper displacing silver from the silver nitrate solution to form copper(II) nitrate and silver metal. The balanced chemical equation for this reaction is: Cu + 2AgNO3 -> 2Ag + Cu(NO3)2.
Cu + 2HNO3 --> Cu(NO3)2 + H2 Looks like it. copper nitrate formed and hydrogen gas just released.
When copper is mixed with copper nitrate, a chemical reaction occurs where the copper in the copper nitrate displaces the copper in the solid copper, forming copper(II) nitrate and releasing nitrogen dioxide gas. This reaction is a redox reaction, where copper is oxidized and the copper ions in the solution are reduced.