0
When the reaction xC yO2 zCO is balanced what should the coefficients be?
Wiki User
∙ 10y ago
x=2, y=1, z=2
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
How do you find the center of the circle given an equation?
A circle with center (xo, yo) and radius r has an equation of the form: (x - xo)2 + (y - yo)2 = r2 which can be rearranged to: x2 - 2xox + xo2 + y2 - 2yoy + yo2 = r2 ⇒ x2 - 2xox +y2 - 2yoy + xo2 + yo2 - r2 = 0 or x2 - 2xox +y2 - 2yoy = r2 - xo2 - yo2 So depending how your equation is given, the center can be read directly from the equation (first form above) or is -1/2 times the coefficients of the x and y terms. eg: What is the center of the circle with equation x2 - 4x + y2 + 6y + 12 = 0 The coefficients of the x and y terms are -4 and +6, so the center is -1/2 times these, namely; (2, -3). Fully rearranging the circle's equation: x2 - 4x + y2 + 6y + 12 = 0 ⇒ (x - 2)2 - 4 + (y + 3)2 - 9 + 12 = 0 [completing the squares] ⇒ (x - 2)2 + (y + 3)2 - 1 = 0 ⇒ (x - 2)2 + (y + 3)2 = 1 ⇒ circle has centre (2, -3) and radius 1.
What is the equation of a circle with center 4 -1 and radius of 8?
The general form for the equation of a circle centre (xo, yo) and radius r is: (x - xo)2 + (y - yo)2 = r2 Which can be rearranged into: x2 - 2xox + y2 - 2yoy = r2 - xo2 - yo2 So a circle with centre (4, -1) and radius 8 has equations: (x - 4)2 + (y + 1)2 = 64 x2 - 8x + y2 + 2y = 47
How do you solve word equation C6H14 plus O2----CO2 plus H20?
Include constants x,y,z as in xC6H14 + yO2 = zCO2 + H2O (notice the number of constants is 1 less than the number of terms). Then equate numbers of like atoms on each side, because atoms are not created or destroyed. So for Oxygen you get 2y=2z+1 and using the other atoms you'll get more equations. Solve these as a set of simultaneous equations. If you get fractions in the answers, multiply all by one same number (ie equally) to get rid of them. That's how.
