Metals and nonmetals form ionic bonds. The metal becomes a positively charged ion, and the nonmetal becomes a negatively charged ion.
No, copper and oxygen would not form a covalent bond. Instead, they would likely form an ionic bond, where copper would donate electrons to oxygen to create a copper oxide compound.
No, bromine and carbon would not form an ionic compound. Carbon typically forms covalent bonds and bromine can also form both covalent and ionic bonds, depending on the element it is reacting with. In this case, a covalent bond would be more likely between bromine and carbon.
No, Mn and Cl would likely not form a covalent compound. Manganese (Mn) typically forms ionic compounds, while chlorine (Cl) is a highly electronegative element that typically forms ionic compounds as well. Therefore, they would most likely form an ionic compound rather than a covalent one.
No, copper and fluorine do not typically form an ionic bond. Copper is a transition metal which tends to form covalent bonds, while fluorine is a highly electronegative element that also forms covalent bonds. In this case, copper and fluorine would likely form a covalent bond rather than an ionic bond.
A diatomic element with a high ionization energy is likely to be an element that forms strong covalent bonds between its atoms. Examples of diatomic elements with high ionization energies include nitrogen (N2) and oxygen (O2) due to the strong triple and double bonds, respectively, they form between their atoms.
No, copper and oxygen would not form a covalent bond. Instead, they would likely form an ionic bond, where copper would donate electrons to oxygen to create a copper oxide compound.
No, bromine and carbon would not form an ionic compound. Carbon typically forms covalent bonds and bromine can also form both covalent and ionic bonds, depending on the element it is reacting with. In this case, a covalent bond would be more likely between bromine and carbon.
No, Mn and Cl would likely not form a covalent compound. Manganese (Mn) typically forms ionic compounds, while chlorine (Cl) is a highly electronegative element that typically forms ionic compounds as well. Therefore, they would most likely form an ionic compound rather than a covalent one.
sulfur
Hydrogen bonds are weak, but they are able to hold the backbones together. If covalent bonds held the templates together instead, the bonds would be even weaker and would likely break.
No, copper and fluorine do not typically form an ionic bond. Copper is a transition metal which tends to form covalent bonds, while fluorine is a highly electronegative element that also forms covalent bonds. In this case, copper and fluorine would likely form a covalent bond rather than an ionic bond.
Someone would most likely receive a shock through the element of electricity.
A diatomic element with a high ionization energy is likely to be an element that forms strong covalent bonds between its atoms. Examples of diatomic elements with high ionization energies include nitrogen (N2) and oxygen (O2) due to the strong triple and double bonds, respectively, they form between their atoms.
For S to make a covalent bond, it would be best to bind it to another non metal. Once such element would be H, thus making the S-H bond which is covalent. Another example would be to bind it to another S, making the disulfide bond, S-S which is also covalent.
An element in group 2 of the periodic table typically forms 2 covalent bonds, as it has 2 valence electrons available for bonding. This allows the element to achieve a full outer shell and attain stability.
The bond between O and F would be a covalent bond (dative/coordinate), if in fact OF existed. More likely it would exist as OF2 (still covalent bonds).
Carbon in the form of diamond or nanotubes. Tin and Lead would be, but they are metals instead.