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The atoms are located within the cell membrane.

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Q: Where are the atoms in an FCC unit cell located?
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What is the number of atoms in FCC unit cell?

A FCC or Face Centered cubic unit cell has 4 atoms. It is calculated like this. There are 8 corners of the unit cell and each corner has one atom.But each atom is shared by 8 unit cells. So. total no. of atoms at corners= 1/8 *8=1 atom . Also, there are 6 faces which have one electron in the centre of it. Each such electron is shared between 2 unit cells. This gives the total no. of atoms at the centre of faces of unit cell=1/2 * 6 = 3 atoms. Adding the two, we get four atoms in an unit cell 1+3=4 atoms.


What is the lowest and highest number of shared and unshared atoms in a unit cell of a FCC structure and a simple cubic structure?

Your question, if I understand it correctly, asks to explain the reasoning behind the coordination number, or number of adjacent atoms, of an atom in a simple cubic structure versus an atom in a face centered cubic structure (FCC).Before we proceed, I would like to clarify one thing:A unit cell of a simple cubic crystal has 1 atom, while a unit cell of FCC crystal has 4 atoms. This may be a little counterintuitive at first, but consider how the atoms are shared. For the simple cubic structure, there are eight individual atoms - one at each corner of the cube. The unit cell, however, has to share each atom with the 8 other adjacent cells. Thus a unit cell gets 8 atoms only 1/8 of the time, hence 8*(1/8) = 1 atom per simple cubic unit cell. Similarly, FCC has the 1 atom from simple cubic, plus half of the 6 atoms on each of it's faces. Thus, FCC has 4 atoms per unit cell.On to the main question. In short, given a homogeneous, perfect crystal the coordination numbers of all the atoms are the same. All atoms are shared equal with their neighbors.For the simple cubic case this is easy to see. Like the simple gumdrop creations of second graders, you can start at any gumdrop to make the creation. Any corner is the same relative to its neighbors as any other corner. For FCC the same is true.


Calculate planer density of 100 plane in FCC?

The 100 plane of an FCC structure is the plane of the unit cell in the zy direction. This face has 1 whole face atom and 4*1/4 corner atoms = 2 atoms. The unit cell length of an FCC structure in relation to the atomic radius (r) of the atoms that make it up is 2sqrt(2)*r Area of atoms = 2*pi r2 Area of plane = [2sqrt(2)*r]2 = 8*r2 Planar density = Area of atoms/ Area of plane = 2*pi r2/ 8*r2 = pi / 4


Nickel has an fcc unit cell with an edge length of 350.7pm calculate the radius of a nickel atom?

175.35 pm


Which is more efficient body centered cubic or face centered cubic?

They are two of the cubic structures for crystals with atoms linked by ionic or covalent bonds. They are also known as BCC and FCC. Table salt, NaCl, and Silicon, for example, assume a FCC structure. For illustrations, please go to the related link.

Related questions

What is the number of atoms in FCC unit cell?

A FCC or Face Centered cubic unit cell has 4 atoms. It is calculated like this. There are 8 corners of the unit cell and each corner has one atom.But each atom is shared by 8 unit cells. So. total no. of atoms at corners= 1/8 *8=1 atom . Also, there are 6 faces which have one electron in the centre of it. Each such electron is shared between 2 unit cells. This gives the total no. of atoms at the centre of faces of unit cell=1/2 * 6 = 3 atoms. Adding the two, we get four atoms in an unit cell 1+3=4 atoms.


What is the lowest and highest number of shared and unshared atoms in a unit cell of a FCC structure and a simple cubic structure?

Your question, if I understand it correctly, asks to explain the reasoning behind the coordination number, or number of adjacent atoms, of an atom in a simple cubic structure versus an atom in a face centered cubic structure (FCC).Before we proceed, I would like to clarify one thing:A unit cell of a simple cubic crystal has 1 atom, while a unit cell of FCC crystal has 4 atoms. This may be a little counterintuitive at first, but consider how the atoms are shared. For the simple cubic structure, there are eight individual atoms - one at each corner of the cube. The unit cell, however, has to share each atom with the 8 other adjacent cells. Thus a unit cell gets 8 atoms only 1/8 of the time, hence 8*(1/8) = 1 atom per simple cubic unit cell. Similarly, FCC has the 1 atom from simple cubic, plus half of the 6 atoms on each of it's faces. Thus, FCC has 4 atoms per unit cell.On to the main question. In short, given a homogeneous, perfect crystal the coordination numbers of all the atoms are the same. All atoms are shared equal with their neighbors.For the simple cubic case this is easy to see. Like the simple gumdrop creations of second graders, you can start at any gumdrop to make the creation. Any corner is the same relative to its neighbors as any other corner. For FCC the same is true.


Calculate planer density of 100 plane in FCC?

The 100 plane of an FCC structure is the plane of the unit cell in the zy direction. This face has 1 whole face atom and 4*1/4 corner atoms = 2 atoms. The unit cell length of an FCC structure in relation to the atomic radius (r) of the atoms that make it up is 2sqrt(2)*r Area of atoms = 2*pi r2 Area of plane = [2sqrt(2)*r]2 = 8*r2 Planar density = Area of atoms/ Area of plane = 2*pi r2/ 8*r2 = pi / 4


Nickel has an fcc unit cell with an edge length of 350.7pm calculate the radius of a nickel atom?

175.35 pm


How do you calculate density of compounds?

p = n x Mr / Vc x NAwhere n is the atoms/unit cell e.g. fcc packing n = 4 and for bcc packing n = 2Mr is the Atomic Mass in g/molVc is the volume/unit cell cm3 = a3 where a can be found by the radius of the atom and the packing used. e.g in bcc packing it is "a = 4r/1.732" . In Fcc packing it is "a= sin (4r)" or "a = cos (4r)"NA is avorgados constant, = 6.023 x1023


Describe Burger vector in fcc material?

Slip in FCC (face centered cubic) crystals occurs along the close packed plane. Specifically, the slip plane is of type {111}, and the direction is of type . In the diagram, the specific plane and direction are (111) and [-110], respectively. Given the permutations of the slip plane types and direction types, FCC crystals have 12 slip systems. In the FCC lattice, the Burgers vector, b, can be calculated using the following equation:[1] : [1] Where a is the lattice constant of the unit cell. Unit Cell of an FCC material.


How do you calculate theoretical density of compound?

p = n x Mr / Vc x NAwhere n is the atoms/unit cell e.g. fcc packing n = 4 and for bcc packing n = 2Mr is the atomic mass in g/molVc is the volume/unit cell cm3 = a3 where a can be found by the radius of the atom and the packing used. e.g in bcc packing it is "a = 4r/1.732" . In Fcc packing it is "a= sin (4r)" or "a = cos (4r)"NA is avorgados constant, = 6.023 x1023


How do you work out the lattice constant for Silver a FCC crystal structure with an atomic radius of 0.1444nm?

You can either draw the unit cell and work it out using trigonometry. Information on the unit cell can be found easily on wikipedia. Or you can shine X rays of a known wavelength in and use the Bragg equation.


What is primitive and non primitive cell?

Primitive unit cells use every lattice point as a unit cell vertex.Non-primitive unit cells, however, contain extra lattice points not at the corners.


What is the number of atoms per unit cell in cubic closed packing arrangement?

Face Centered Cubic (FCC) crystal structure has 4 atoms contained per unit cell. The relationship of of radius (R) to the lattice parameter (a) is 4R = a(sqrt(2)). In terms of lattice parameter (a)it is equal to, a = 2R(sqrt(2)).


Which is more efficient body centered cubic or face centered cubic?

They are two of the cubic structures for crystals with atoms linked by ionic or covalent bonds. They are also known as BCC and FCC. Table salt, NaCl, and Silicon, for example, assume a FCC structure. For illustrations, please go to the related link.


What is crystals in science terms?

Crystals are those substances which possess Atoms arranged in a reagular manner.They can be either BCC, FCC or SC.