At 0C and 1 atm, the gas that is best described by the ideal gas law is helium.
The ideal gas law measures pressure in pascals (Pa) or atmospheres (atm).
L •atm/mole•k
The "Ehow" website containing an excellent article on determining the ATM to molarity. It is, however, a most complex process and requires a barometer, extra long tape measure and a thermometer.
25C is 298K. 52C is 325K. Assuming linearity (an ideal gas), P=3*325/298=3.27 atm.
Molecules of an ideal gas are considered to be point masses that do not have any volume, do not interact with each other, and collide with each other and the container walls in perfectly elastic collisions. The behavior of ideal gases is described by the ideal gas law, which relates pressure, volume, and temperature.
The ideal gas law measures pressure in pascals (Pa) or atmospheres (atm).
L •atm/mole•k
L •atm/mole•k
The volume is 251,6 litres.
L •atm/mole•k
If a sample of an ideal gas has a volume of 2.22 at 287 K and 1.13 atm what will the pressure be when the volume is 1.47 L and the temperature is 306 K?
The internal energy of an ideal gas is directly related to its temperature. As the temperature of an ideal gas increases, its internal energy also increases. This relationship is described by the equation for the internal energy of an ideal gas, which is proportional to the temperature of the gas.
The "Ehow" website containing an excellent article on determining the ATM to molarity. It is, however, a most complex process and requires a barometer, extra long tape measure and a thermometer.
25C is 298K. 52C is 325K. Assuming linearity (an ideal gas), P=3*325/298=3.27 atm.
Molecules of an ideal gas are considered to be point masses that do not have any volume, do not interact with each other, and collide with each other and the container walls in perfectly elastic collisions. The behavior of ideal gases is described by the ideal gas law, which relates pressure, volume, and temperature.
Using the ideal gas law (PV = nRT), we can calculate the new pressure of the gas in the aerosol can. Given that the initial pressure (P1) is 1.8 ATM and the initial temperature (T1) is 25°C, we can rearrange the formula to find the new pressure (P2) at 475°C. Since the volume (V), moles of gas (n), and gas constant (R) remain constant, we can solve for P2: P2 = (P1 * T2) / T1 = (1.8 ATM * 748 K) / 298 K ≈ 4.5 ATM.
The volume occupied by a mole of an ideal gas can be calculated using the ideal gas law equation: PV = nRT. Convert the pressure to atm (1 atm = 760 mmHg), and the temperature to Kelvin (25.0°C = 298 K). Then substitute the values into the equation and solve for volume (V).