Van der Waals - they're the weakest.
Hydrogen bonding
Van der Waals forces
NaOH has the higher melting point. The reason is since NaOH is an ionic compound, thus meaning that the intermolecular forces (the forces that hold the compound together) between Sodium+ and Hydroxide- are ionic - ionic forces. The charges keep them together. Ionic forces are ALOT stronger than other intermolecular forces such as dispersion, dipole-dipole, or even hydrogen bonding. CH3OH (Methanol) has a lower melting point that Sodium Hydroxide since the intermolecular forces it entails are: Dispersion, dipole-dipole, and hydrogen bonding between Hydrogen and Oxygen. It will take LESS energy to break these attractions, than the energy required to break the attraction forces between the ionic compound NaOH.
one with hydrogen bonding.
The stronger the intermolecular forces, the higher the melting point and boiling point. The weaker the intermolecular forces, the lower the melting and boiling points are.
Hydrogen bonding
The hydrogen bonding present between the two molecules is known as intermolecular hydrogen bonding, the molecules may be similar or may be dissimilar. The molecules having intermolecular hydrogen bonding have high melting and boiling points and low volatility. They are more soluble in water as compared to the molecules having intramolecular hydrogen bonding.
Van der Waals forces
Hydrogen bonding, which is the strongest of the intermolecular forces.
hydrogen bonding increases the intermolecular attractions and therefore increases the boiling point and melting point.
Hydrogen-bonding molecules
NaOH has the higher melting point. The reason is since NaOH is an ionic compound, thus meaning that the intermolecular forces (the forces that hold the compound together) between Sodium+ and Hydroxide- are ionic - ionic forces. The charges keep them together. Ionic forces are ALOT stronger than other intermolecular forces such as dispersion, dipole-dipole, or even hydrogen bonding. CH3OH (Methanol) has a lower melting point that Sodium Hydroxide since the intermolecular forces it entails are: Dispersion, dipole-dipole, and hydrogen bonding between Hydrogen and Oxygen. It will take LESS energy to break these attractions, than the energy required to break the attraction forces between the ionic compound NaOH.
These are the hydrogen bonds between molecules.
one with hydrogen bonding.
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hydrogen
They are the primary intermolecular attractive forces that act between nonpolar molecules. -Apex.