B
The correct orbital diagram for boron is 1s^2 2s^2 2p^1, showing the distribution of its 5 electrons among the 2s and 2p orbitals.
The orbital filling diagram of boron would show two electrons in the first energy level (1s orbital) and one electron in the second energy level (2s orbital). Boron has an electron configuration of 1s^2 2s^1.
The correct orbital diagram for sulfur can be represented as: 1s2 2s2 2p6 3s2 3p4. This indicates that sulfur has two electrons in the 1s orbital, two in the 2s orbital, six in the 2p orbital, two in the 3s orbital, and four in the 3p orbital.
The electron configuration of Boron-11 is 1s2 2s2 2p1. Boron has 5 electrons, with 2 in the 1s orbital, 2 in the 2s orbital, and 1 in the 2p orbital.
The correct orbital diagram for sulfur (atomic number 16) is 1s2 2s2 2p6 3s2 3p4. This represents the distribution of electrons in the respective energy levels and orbitals within the sulfur atom.
The correct orbital diagram for boron is 1s^2 2s^2 2p^1, showing the distribution of its 5 electrons among the 2s and 2p orbitals.
The orbital filling diagram of boron would show two electrons in the first energy level (1s orbital) and one electron in the second energy level (2s orbital). Boron has an electron configuration of 1s^2 2s^1.
The correct orbital diagram for sulfur can be represented as: 1s2 2s2 2p6 3s2 3p4. This indicates that sulfur has two electrons in the 1s orbital, two in the 2s orbital, six in the 2p orbital, two in the 3s orbital, and four in the 3p orbital.
The orbital configuration for boron is 1s2 2s2 2p1. This means that boron has two electrons in the 1s orbital, two in the 2s orbital, and one in the 2p orbital.
The electron configuration of Boron-11 is 1s2 2s2 2p1. Boron has 5 electrons, with 2 in the 1s orbital, 2 in the 2s orbital, and 1 in the 2p orbital.
Electronic configuration of boron: [He]2s2.2p1.
The correct orbital diagram for sulfur (atomic number 16) is 1s2 2s2 2p6 3s2 3p4. This represents the distribution of electrons in the respective energy levels and orbitals within the sulfur atom.
The orbital diagram for V5 consists of five electrons in the 3d orbital and no electrons in the 4s orbital.
The standard electron configuration form of boron is 1s2 2s2 2p1. The noble gas form is [He] 2s2 2p1.
The electron orbital pattern of boron is 1s2 2s2 2p1. This means it has 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, and 1 electron in the 2p orbital.
The ionization energy of boron is lower than beryllium because removing an electron from boron involves taking it out of the 2p orbital, which is higher in energy than the 1s orbital of beryllium. This makes it easier to remove an electron from the 2p orbital of boron, resulting in a lower ionization energy.
1s2 2s2 2p1 is the electron configuration for boron, and it has a total of 5 electron. Just fill the orbital up with the elements total number of electrons until no more are left, then u have your electron configuration