Lead
2K(I) + CuCl2 => 2KCl + Cu(I)2 The (I) is iodide, because the capital I and lowercase l look the same. This is a double replacement reaction, where copper (II) iodide comes out of solution, because it's not soluble, assuming that both of those are in solution.
The isoelectronic of iodide (I-) is xenon (Xe), because both species have the same number of electrons.
Sodium chloride (NaCl) and sodium iodide (NaI) are both ionic compounds, with NaCl being composed of sodium ions and chloride ions, and NaI being composed of sodium ions and iodide ions. The main difference between the two is the anion present in each compound, chloride in NaCl and iodide in NaI, which affects their solubility, reactivity, and physical properties. Sodium iodide tends to be more reactive and soluble in polar solvents compared to sodium chloride.
Salt and baking powder (sodium bicarbonate) are both ionic compounds. Anything that is a metal and nonmetal bonded together is an ionic compound.
When potassium iodide reacts with barium nitrate, a double displacement reaction occurs. The potassium ions and barium ions switch places to form potassium nitrate and barium iodide. Both products are insoluble and will form a precipitate.
2K(I) + CuCl2 => 2KCl + Cu(I)2 The (I) is iodide, because the capital I and lowercase l look the same. This is a double replacement reaction, where copper (II) iodide comes out of solution, because it's not soluble, assuming that both of those are in solution.
Silver chloride (AgCl) is insoluble in both cold and hot water.
The isoelectronic of iodide (I-) is xenon (Xe), because both species have the same number of electrons.
Sodium chloride (NaCl) and sodium iodide (NaI) are both ionic compounds, with NaCl being composed of sodium ions and chloride ions, and NaI being composed of sodium ions and iodide ions. The main difference between the two is the anion present in each compound, chloride in NaCl and iodide in NaI, which affects their solubility, reactivity, and physical properties. Sodium iodide tends to be more reactive and soluble in polar solvents compared to sodium chloride.
Take a few drops of both samples and add some lead nitrate. A yellow precipitate indicates lead iodide and it gives the inference that it contains iodide ions, hence the solution of sodium iodide.
They are different ionic compounds, sodium chloride is NaCl, sodium iodide is denoted NaI. Both are soluable in water, though NaI is more soluable. They look quite similar as both are white crystalline salts. They are used for different purposes though.
Both are salts, contain sodium and contain halogens (iodine and chlorine are halogens).
Salt and baking powder (sodium bicarbonate) are both ionic compounds. Anything that is a metal and nonmetal bonded together is an ionic compound.
When potassium iodide reacts with barium nitrate, a double displacement reaction occurs. The potassium ions and barium ions switch places to form potassium nitrate and barium iodide. Both products are insoluble and will form a precipitate.
Really, there is no reaction to speak of. The two are sometimes used together as a cough expectorant. But it is really the ammonium chloride doing the work by irritating the esophagus, thus causing more fluid excretion and causing a loose cough.
Neither, iodized salt is just a mixture of sodium chloride and potassium iodide (both neutral salts).
You can show the presence of Sulphate in a mixture by adding barium chloride solution followed by dil HCl. A white precipitate that does not dissolvev in dil HCl indicates the presence of sulphate ioins. Ba2+ (aq) + SO4^2- (aq) ---------> BaSO4 (s) Iodide ions can be shown by adding to the suspected iodide a solution of lead nitrate where upon a brilliant yellow ppt is thrown down Pb2+ (aq) + 2 I- (aq) --------> PbI2 (aq) Also addition of silver nitrate will give a yellow ppt which is insoluble in ammonia solution. Ag+ (aq) + I- (aq) ----------> AgI (s)