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Which metal ion is reduced by lead?

Updated: 8/11/2023
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Calcium, Mercury, cadmium, or potassium?

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Q: Which metal ion is reduced by lead?
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When electroplating metal ions (e.g. Chromium) are deposited as metal at the cathode. The metal ion is reduced. The concentration of chromium ion drops as a result.


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Lead iodide is not a correct name. Lead is a transition metal and can form more than one ion. The charge of the lead ion should be in the name. For example, lead(II) iodide, which would be PbI2. Lead(IV) iodide would be PbI4.


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O2- ion is known as peroxide in English. As it is not a transition metal ion, it is not able to be written any other way. If it were a transition metal such as Lead (Pb), the Pb4+ ion can be called lead (IV) or plumbic. Lead (IV) is written in the Stock method with roman numerals representing the electrons in the ion. Plumbic is written in the Classical method with the suffixes "ic" and "ous". As some transition metals have two different ions, "ic" is added to the higher ion name while "ous" is added to the lower ion name.


What is the charge on the lead ion in PbS2?

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When an electron is tranferred to a positive (mono elementary) ion (eg. a metal ion, like Al3+) this ion is 'reduced' to an (elemental) atom (Fe). For comlex ions (eg. ammonium NH4+) it is essentially in the same way: it gets 'reduced', but not all to 'elements' (eg. 2NH4+ + 2e- --> 2NH3 + H2)


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This would be an ionic compound. The lead (IV) ion is a metal, so it would be a cation (positive ion), and the numerals tell us it has a charge of 4+. The oxygen ion is a non-metal, so it would be an anion (negative ion) and it is in group 6A, so it would have a charge of 2-.The ionic compound needs to have a net charge of zero, so we would need two oxygen ions to balance out the charge of each lead (IV) ion.Therefore, the correct formula for lead (IV) oxide is PbO2.


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A non-metal ion and a metal ion


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