PO43-
When HPO42- acts as an acid, it donates a proton to form H2PO4-. H2PO4- is the conjugate base of HPO42-.
PO43-
H3PO4==============Phosphoric acid.
'Conjugate' means ONE proton more (acid) or less (base) than the described acid or base respectively:So the conjugate acid of PO43- (phosphate) is HPO42- (monohydrogen phosphate)
its an acid, H2PO4- is called dihydrogen phosphate ion. It is the conjugate base of Phosphoric Acid H3PO4 and the conjugate acid of monohydrogen phosphate ion HPO42
When HPO42- acts as an acid, it donates a proton to form H2PO4-. H2PO4- is the conjugate base of HPO42-.
PO43-
PO43- (phosphate) is the conjugate base of HPO42- (monohydrogen phosphate)
H3PO4==============Phosphoric acid.
'Conjugate' means ONE proton more (acid) or less (base) than the described acid or base respectively:So the conjugate acid of PO43- (phosphate) is HPO42- (monohydrogen phosphate)
its an acid, H2PO4- is called dihydrogen phosphate ion. It is the conjugate base of Phosphoric Acid H3PO4 and the conjugate acid of monohydrogen phosphate ion HPO42
SO32
H3PO4 (aq) + H2O (l) ---> 2H3O+ (aq) + PO4-3 (aq)donor acid + acceptor base ---> conjugate acid + conjugate basethe answer above is wrongto form a conjugate, the ion H2PO4 - must lose a hydrogen ion H+i.eH2PO4 - -H+ = HPO4 2-(conjugate base)
The conjugate base and conjugate acid for HS04 is: Conjugate acid is H2SO4 Conjugate base is SO42
This is a Bronsted question. Hs- is the acid in this which makes H2O a base. Therefore S-2 is the conjugate base and the H3O+ hydronium ion is the conjugate acid.
The conjugate base of NH3 is NH2-, formed by removing a proton (H+) from NH3.
The conjugate base for CH3CH2COOH is CH3CH2COO-.