In this reaction, Zn(s) is the reducing agent and HCl(aq) is the oxidizing agent. Zn(s) loses electrons to form Zn2+ ions, while HCl(aq) gains electrons to form H+ ions and Cl- ions.
I believe it is HClaq with the aq in subscript
=> NaClaq + H2O + heat
Since HCl is a strong acid and Ba(OH)2 is a strong base, the reaction that takes place is a simple neutralization reaction. The reaction is represented by the net ionic equation: H+(aq) + OH-(aq) ---> H2O This is the equation whenever any strong acid and strong base react.
Sodium chloride (NaCl) would be left behind after evaporating the solution to dryness. This is because when sodium hydroxide (NaOH) reacts with hydrochloric acid (HCl), it forms sodium chloride and water. Evaporating the water leaves behind solid sodium chloride.
If you added less than the amount needed in part (b) of K2SO3, what would be the limiting reactant? If you added more than the amount needed in part (b) of K2SO3, what would be the limiting reactant? Which situation would create the most SO2 gas?excess HClexcess K2SO3 excess H2Oexcess KClperfectly matched amounts of HCl and K2SO3