O = oxygen atom
O2 = dioxygen molecule
O3 = ozone molecule
H2 = dihydrogen molecule
H2 (Hydrogen) reacts with O2 (Oxygen) to form water. 2 H2 + O2 --> 2 H2O
2h2o -> 2h2 + o2
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
H2
2H2(g) + O2(g) = 2H2O(l) (Water) or H2(g) + O2(g) = H2O2(l) ( Hydrogen peroxide).
= H2+O2 =2H2+O2=2H2O
H2 (Hydrogen) reacts with O2 (Oxygen) to form water. 2 H2 + O2 --> 2 H2O
H2 and O2.
Balanced equation first. 2H2 + O2 >> 2H2O 1.42 mol H2 ( 1mol O2/2mol H2 ) = 0.71mol O2 to react with H2
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
In order to have a balanced equation, adding the reactant H2 And O2 (H2+O2) have to come out equal on the product side and the reactant side. This would look like H2+O2 = H2O2
Balanced equation. 2H2 + O2 -> 2H2O 355 grams O2/32 grams = 11.1 moles O2 check for limiting reactant 11.1 moles O2 (2 mole H2/1 mole O2) = 22.2 mole H2 and H2 has no where near that many moles, so limits and drives reaction so, as they are one to one...... 22.2 moles of H2O are produced
2h2o -> 2h2 + o2
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
Well, where is your stoichiometric equation that represents the (typical!) reaction between dioxygen, and dihydrogen? H2(g)+12O2(g)→H2O(l) I think the stoichiometry is clear with regard to your problem.
o2 is a symbol. A formula is something like O2 + H2 -> H20
H2