4p
A bromine atom with a mass number of 79 loses one electron to become a bromine ion with a negative 1 charge. This occurs when the atom gains an extra electron, giving it a full outer electron shell of 8 electrons, thus forming the Br- ion.
In the reaction, bromine gains an electron to become a bromide ion with a negative charge. This process is known as reduction because the bromine atom is gaining an electron, which results in a decrease in its oxidation state.
Bromine can gain a stable outer electron shell by accepting one electron to fill its 4p orbital, achieving a full valence shell of eight electrons. This allows it to have the electron configuration of a noble gas, like argon, and become a stable ion.
Bromine tends to gain one electron to achieve a stable electron configuration, making it an electron acceptor (accepts one electron).
Bromine loses an electron and forms a bromide ion by gaining one electron in the reaction with sodium. Sodium donates its electron to bromine, making the bromine atom gain one electron and become a bromide ion during the reaction.
A bromine atom with a mass number of 79 loses one electron to become a bromine ion with a negative 1 charge. This occurs when the atom gains an extra electron, giving it a full outer electron shell of 8 electrons, thus forming the Br- ion.
In the reaction, bromine gains an electron to become a bromide ion with a negative charge. This process is known as reduction because the bromine atom is gaining an electron, which results in a decrease in its oxidation state.
Bromine can gain a stable outer electron shell by accepting one electron to fill its 4p orbital, achieving a full valence shell of eight electrons. This allows it to have the electron configuration of a noble gas, like argon, and become a stable ion.
Bromine tends to gain one electron to achieve a stable electron configuration, making it an electron acceptor (accepts one electron).
Bromine loses an electron and forms a bromide ion by gaining one electron in the reaction with sodium. Sodium donates its electron to bromine, making the bromine atom gain one electron and become a bromide ion during the reaction.
Bromine tends to gain one electron to become a Br- ion.
that's a stupid question
Bromine typically gains one electron when forming an ion to achieve a stable electron configuration. The electron configuration for a bromine ion is [Kr] 4d10 5s2 5p6, which is the same as that of a noble gas.
Bromine has 7 electrons in its outer shell and needs to gain one electron to have a full outer shell and become an ion. It will gain this electron from an atom that has one electron in its outer shell such as Lithium or Sodium.
Normally, bromine forms an anion, because it gains one electron to have a full octet, and is then negative. (Br1-) However, bromine can from a cation, as is the case when using N-bromosuccinimide (Br+ is given off).
An atom of bromine-79 can become a bromide ion with a -1 charge by gaining an electron. Bromine-79 has 35 protons and 44 neutrons, making it electroneutral. By gaining an electron, it attains the electron configuration of a stable halide ion with 36 electrons, resulting in a net charge of -1.
Selenium and bromine can form an ionic bond, where selenium, a nonmetal, gains electrons to become a negative ion, and bromine, a halogen, loses electrons to become a positive ion.