To obtain solid lead iodide from 20cm3 of aqueous lead nitrate, you would need a source of iodide ions (e.g., potassium iodide), a filtration apparatus to separate the solid lead iodide from the solution, a beaker or container to collect the solid, and a drying oven or desiccator to dry the collected solid. Optional equipment includes a stirring rod and a hot plate to facilitate the reaction.
Nitric acid is required to produce ammonium nitrate. Ammonium nitrate is formed by reacting nitric acid with ammonia.
The formula of calcium iodide is CaI2. This is because calcium is a group 2 element with a 2+ charge, while iodide is a group 17 element with a 1- charge. Therefore, to balance the charges, two iodide ions are needed for each calcium ion.
To determine the number of grams of lithium nitrate needed to make 250 grams of lithium sulfate, you need to calculate the molar mass of lithium sulfate and lithium nitrate, then use stoichiometry to find the ratio of lithium nitrate to lithium sulfate. Finally, apply this ratio to find the mass of lithium nitrate needed for the reaction. Lead sulfate is not involved in this calculation as it is not part of the reaction between lithium nitrate and lithium sulfate.
It sounds like you're describing Lugol's iodine. It's not technically "required," it's just that's what the recipe is. Actually, in Lugol's iodine, KI is needed to improve the dissolution of iodine in water.
The unhealthy plant likely needed nitrate ions (NO3-) to get the right levels of nitrogen. Nitrate is a common form of nitrogen that plants can absorb and use for growth and development.
530,3 g potassium iodide are needed.
The leaf was rinsed in water to rehydrate it. Iodine solution is an aqueous solution of iodine/potassium iodine - potassium tri-iodide; water is needed inside the leaf to enable penetration by diffusion.
Nitrate is needed for protein metabolism.
You need 26,49 g silver nitrate.
These reagents doesn't react.
Nitric acid is required to produce ammonium nitrate. Ammonium nitrate is formed by reacting nitric acid with ammonia.
The formula of calcium iodide is CaI2. This is because calcium is a group 2 element with a 2+ charge, while iodide is a group 17 element with a 1- charge. Therefore, to balance the charges, two iodide ions are needed for each calcium ion.
You need 145,337 g silver nitrate.
The mass of silver nitrate is 30,6 g.
The post office of the cell, the Golgi apparatus packages proteins and other molecules. Then the Golgi deliver them to where they are needed.
To determine the number of grams of lithium nitrate needed to make 250 grams of lithium sulfate, you need to calculate the molar mass of lithium sulfate and lithium nitrate, then use stoichiometry to find the ratio of lithium nitrate to lithium sulfate. Finally, apply this ratio to find the mass of lithium nitrate needed for the reaction. Lead sulfate is not involved in this calculation as it is not part of the reaction between lithium nitrate and lithium sulfate.
The amount of excess potassium iodide depends on the stoichiometry of the reaction between potassium iodide and copper sulfate. One equivalent of potassium iodide is needed to react with one equivalent of copper sulfate. Excess potassium iodide would be any amount added beyond this stoichiometric ratio.