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a) I(g) + e → I-(g)
b) I2(g) → 2I(g) c) I(g) → I+(g) + e
d) Na(g) + I(g) → NaI(s)
e) Na(s) + 1/2I2(s) → NaI(s)


The correct answer out of these choices is clearly a) I(g) + e → I-(g). That is the right answer.

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