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The hydrophobicity of a molecule increases with longer contiguous chains of hydrocarbons. The -OH in 1-propanol is on the first of the three carbons, leaving the second and third carbons to form a larger hydrophobic molecular surface. In 2-propanol the OH on the central (second) carbon breaks up the overall surface hydrophobicity.

The reason for this is that the O is an electron drawing group. As such, O will have an effect on the bonds between the C it's connected to as well as each bond made by that C. Also, the closer O is to another atom in the molecule, the stronger the effect. In 1-propanol, O is further from the third carbon, thus having a lesser effect on the dipole moment of that carbon. In 2-propanol, the O effects the dipole moments of the first and third carbons equally.

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14y ago
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13y ago

the boiling point is used to distinguish them. 1-propanol will have high boiling point than the 2-boiling point.

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Q: Why 1-propanol is more hydrophobic or having lower polarity than 2-propanol?
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