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for most of the lanthanides the ionsiation energy to lose a fourth electron will be so large that it cannot be compensated for by bond formation,this is due to the 4f electrons which are shielded and can be regarded as "core electrons".in general it can be said that I4~2(I3)~4(I2)~8(I1)
however for Eu and Yb +2 will be the favoured O.S. due to the presence of a half filled(7e) and a filled 4f shell(14e) respectively
the +4 oxidation state is also possible
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