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When the both the cations and anions are absent from the crystal lattice it is called Schottky defect. This defect is shown when the anions and cations have comparable size. The Frenkel defect is shown by ionic molecules when their is a large difference in the size of anions and cations. The smaller anions are very much mobile and they occupy interstitial site. AgBr has cations and anions with comparable size and hence it shows Schottky defect but the Ag+ ion is very much mobile and it easily occupies interstitial place getting dislocated from its original place, that's why the ionic crystal AgBr shows both Schottky and Frenkel defects.
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Why does AgBr show both Frenkel and Schottky defects?
The radius ratio for AgBr is intermediate. Thus it shows both frenkel and schottky defects. The major defect in AgBr is the Frenkel defect. It has a rocksalt structure i.e. CCP lattice of of Br with atoms of Ag occupying all octahedral holes.Ag moves from octahedral to tetrahedral sites causing only cations to precipitate. Schottky defect arise due to missing of ions from their lacttice point and frenkel arise when the mmissing ions occupy interstitial sites. in AgBr, ag+ ion is small in size and when removed from lacttice point they can occupy interstitial site and therefore show both frenkel and schottky defect. SCHOTTKY Defect in AgBr is exhibited due to precipitation of both Cations and Anions.
What is the chemical formula AgBr?
AgBr is the chemical formula of silver bromide.
What is the mass of NaBr that will be produced from 42.7 g of AgbR?
Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] First check that the given equation is balanced ... it isn't ... so the first thing to do is balance the equation: balancing Na: 2Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] and everything is now balanced so we've got the balanced equation molar mass AgBr = 107.87 + 79.90 = 187.77 g/mol mol AgBr available = 42.7 g AgBr x [1 mol / 187.77 g] = 0.2274 mol AgBr from the balanced equation the mole ratio AgBr : Na2S2O3 = 1 : 2 so mol Na2S2O3 required = 0.2274 mol AgBr x [ 2 mol Na2S2O3 / mol AgBr] = 0.455 mol Na2S2O3 (to 3 sig figs)
What is AgBr?
Silver Bromide
What is compound formula for silver bromide?
Silver will have a +1 and bromate is -1 so they combine in a 1:1 ratio. The formula would be AgBrO3.
Why AgBr shows both frenkel and schottky defect?
because the size of ions are enough to show both defects
Why does AgBr show both Frenkel and Schottky defects?
The radius ratio for AgBr is intermediate. Thus it shows both frenkel and schottky defects. The major defect in AgBr is the Frenkel defect. It has a rocksalt structure i.e. CCP lattice of of Br with atoms of Ag occupying all octahedral holes.Ag moves from octahedral to tetrahedral sites causing only cations to precipitate. Schottky defect arise due to missing of ions from their lacttice point and frenkel arise when the mmissing ions occupy interstitial sites. in AgBr, ag+ ion is small in size and when removed from lacttice point they can occupy interstitial site and therefore show both frenkel and schottky defect. SCHOTTKY Defect in AgBr is exhibited due to precipitation of both Cations and Anions.
What is the chemical formula AgBr?
AgBr is the chemical formula of silver bromide.
What does the symbol AgBr stand for in chemistry?
AgBr is the chemical formula (not symbol) of silver bromide.
What is the mass of NaBr that will be produced from 42.7 g of AgbR?
Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] First check that the given equation is balanced ... it isn't ... so the first thing to do is balance the equation: balancing Na: 2Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] and everything is now balanced so we've got the balanced equation molar mass AgBr = 107.87 + 79.90 = 187.77 g/mol mol AgBr available = 42.7 g AgBr x [1 mol / 187.77 g] = 0.2274 mol AgBr from the balanced equation the mole ratio AgBr : Na2S2O3 = 1 : 2 so mol Na2S2O3 required = 0.2274 mol AgBr x [ 2 mol Na2S2O3 / mol AgBr] = 0.455 mol Na2S2O3 (to 3 sig figs)
What is AgBr?
Silver Bromide
Is AgBr a element or a compound?
Element
Is AgBr an element or a compound?
Compound
What is compound formula for silver bromide?
Silver will have a +1 and bromate is -1 so they combine in a 1:1 ratio. The formula would be AgBrO3.
What is the appropriate name for AgBr?
Silver Bromide
What is the chemical formula for silver bromide?
AgBr
What color is AgBr as a precipitate?
Its yellow in colour
