Green trousers appear black when exposed to red light because red light does not contain any wavelengths that are able to be absorbed or reflected by the green dye in the trousers. As a result, the dye appears dark or black.
To make green appear black, shine red light on it. Green absorbs red light, so when red light is shone on green, the green will appear black.
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Leaves are green because green is the color they reflect, or reject. If you exposed a green plant to only green light, it would perish. Yellow is close to green and it's likely that an all-yellow light would not allow green plants to thrive. This question practically calls out for a science experiment now that monochrome (one color) fluorescent lights are available.
You can demonstrate this by placing a green plant under a glass container with a light source and snuffing out a burning candle inside the container. As the plant photosynthesizes in the light, it releases oxygen, allowing the candle to be relit. This shows that green plants release oxygen during photosynthesis when exposed to light.
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Green trousers would appear black when exposed to red light because the red light does not contain any green wavelengths to reflect off the trousers. Without any green light to reflect, the trousers will appear black in the presence of red light.
Under a red spotlight, his jacket will not show up because it is red. His white shirt will appear red and his green trousers will appear black. This is because The red jacket is the same color as the light. His white shirt will turn red, since white reflects all colors, and since red is the only color, the white shirt reflects that color. His green trousers will appear black because there is no green that reflects off his trousers.
Something takes light in e.g. black trousers
Black light is actually ultraviolet (UV) light, which is not visible to the human eye. When exposed to objects or surfaces that contain fluorescent or phosphorescent materials, they may appear to "glow" or fluoresce in colors such as green, yellow, or blue under black light.
Bromine
To make green appear black, shine red light on it. Green absorbs red light, so when red light is shone on green, the green will appear black.
When green light is mixed with red light, the colors combine and form black. This is known as subtractive color mixing, where red light subtracts the green color from the green shirt, resulting in it appearing black under red light.
While the ball would still be green it will appear black. Anything green absorbed all colours except green. The green light is reflected to your eyes which makes it look green. Thus in red light (with no green in it) the red will be absorbed and no green light can be reflected to your eyes so the ball will look black.
Chlorophyll is green and nothing will ever change that
Black isn't a light ray, its an absence of light. Red and green light assuming equal proportions makes yellow light
Yes, certain varieties of tourmaline may exhibit fluorescence when exposed to UV/black light due to trace elements within the crystal structure. The fluorescence can range from a variety of colors including blue, green, and pink.
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