Because the electronegativities values of Be and Mg are high in comparission of other elements of the group. These two metals form poler covalent bond with hydrogen and due to polarity the units of these hydrides are linked to gather in the form of chain by hydrogen bond. so thier hydrides are called polymeric hydrides.
Beryllium and magnesium have high charge density and small atomic size, making it energetically more favorable for them to form covalent bonds with hydrogen atoms to create polymeric hydrides. The formation of ionic hydrides would require a stronger electron transfer, which is less favorable due to the large ionization energy of these metals.
It may be Magnesium Tritide, Which is a form of Magnesium hydride, containing Radioactive hydrogen(or Tritium) in place of hydrogen. Its formula can also be written as Mg3H2
Beryllium typically forms covalent bonds with atoms like oxygen, which can form a beryllium oxide compound. Beryllium can also form ionic bonds with atoms like chlorine, which can form beryllium chloride.
Magnesium reacts with oxygen to form magnesium oxide, and reacts with hydrogen to form magnesium hydride. There is no single chemical reaction that combines all three elements together to form a specific compound.
The hydride formula for xenon is XeH4. Xenon typically forms compounds with fluorine, oxygen, and nitrogen, but it can also form a hydride by bonding with hydrogen.
Beryllium and magnesium have high charge density and small atomic size, making it energetically more favorable for them to form covalent bonds with hydrogen atoms to create polymeric hydrides. The formation of ionic hydrides would require a stronger electron transfer, which is less favorable due to the large ionization energy of these metals.
It may be Magnesium Tritide, Which is a form of Magnesium hydride, containing Radioactive hydrogen(or Tritium) in place of hydrogen. Its formula can also be written as Mg3H2
When hydrochloric acid reacts with magnesium, it produces magnesium chloride and hydrogen gas as the products. This is a single replacement reaction where the more reactive magnesium displaces hydrogen in the acid to form the products.
About this type of question: My answer is that beryllium is small in size. So, the charge density (charge/radius) is extremely high. So, the force of attraction between the electrons in orbitals and proton in nucleus is very strong. When beryllium is encountered with the other elements (i.e. chlorine), the electrons cannot loss to environment(due to strong force of attraction), but the beryllium will be polarised to become positively charge and hence attract the electron from other elements to form the covalent compound (BeCl2 which is Cl-Be-Cl). So the beryllium hydride is a polar covalently bonded compound.
Beryllium typically forms covalent bonds with atoms like oxygen, which can form a beryllium oxide compound. Beryllium can also form ionic bonds with atoms like chlorine, which can form beryllium chloride.
Magnesium burns bright white. It is often used in the production of fireworks. Magnesium is the most common metal that burns white, but titanium , aluminum , and beryllium can be mixed to form compounds that also form bright white light.
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The elements belonging to the alkaline earth family are beryllium, magnesium, calcium, strontium, barium, and radium. They are found in Group 2 of the periodic table and share similar chemical properties such as forming 2+ cations and reacting with water to form alkaline solutions.
Beryllium and phosphorus can form an intermetallic compound called beryllium phosphide (Be3P2).
Magnesium reacts with oxygen to form magnesium oxide, and reacts with hydrogen to form magnesium hydride. There is no single chemical reaction that combines all three elements together to form a specific compound.
The hydride formula for xenon is XeH4. Xenon typically forms compounds with fluorine, oxygen, and nitrogen, but it can also form a hydride by bonding with hydrogen.
The compound MgO2 is magnesium peroxide. All of the other alkaline earth metals, except for beryllium, will form peroxides with a similar formula, such as CaO2 and SrO2. Note: The 2 after the O should be a subscript. Unfortunately, subscripts and superscripts are not currently functioning.