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haloarenes are less reactive than haloalkanes because:
1. resonance effect more the resonatinsg structures,more the stability
2.difference in hybridisation of the C-X bond i.e.,in haloalkanes,the hybridisation is sp3 whereas in haloarenes it is sp2 hybridised.As sp2 is more electronegative therefore bond length is shorter and hence stronger.
these are the major reasons.
What else can I help you with?
Why alkyl halides give alcohol with aqueous KOH whereas wit alcoholic KOH they give alkenes?
Alkyl halides undergo an E2 elimination reaction with alcoholic KOH to form alkenes due to the basicity of KOH in an alcohol solvent. However, with aqueous KOH, alkyl halides undergo an SN2 substitution reaction to form alcohols. The solvents play a significant role in determining the type of reaction that occurs.
Why alkyl halides undergo elimination reaction?
Alkyl halides undergo elimination reactions, such as E2 and E1, to form alkenes and hydrogen halides. This occurs in the presence of a base or nucleophile due to the tendency of the halide to leave, resulting in the formation of a double bond. The presence of a strong base favors elimination over substitution reactions.
Why furan do not show nucleophilic subtitution reaction?
Furan does not typically undergo nucleophilic substitution reactions because of its aromatic nature, which offers stability due to delocalization of the pi electrons in the ring. This makes furan less reactive towards nucleophilic attack compared to non-aromatic compounds.
Is it possible for an alkyl halide to undergo sn1 and also sn2 reactions?
Yes an alkyl halide can undergo both Sn1 and Sn2 reactions - it just depends on what kind of alkyl halide it is. Methyl halides such as CH3Br/CH3Cl/CH3I, etc. are most suitable for Sn2 reactions because they are less sterically hindered by R-groups (they are not "bulky"). This allows for easy attack by the nucleophile. Primary alkyl halides (RCH2X) are also most suitable for Sn2 because of the same reason above Secondary alkyl halides can undergo both Sn1 and Sn2 reactions, this depends on other factors such as solvent and leaving group and nucleophile. If the solvent is polar aprotic, the reaction will go Sn2, if polar protic - Sn1. Tertiary alkyl halides (alkyl halides with 4 r-groups) do not go Sn2 because they are bulky and the R-groups stabilize the carbocation by hyperconjugation and inductive effect.
Why do you think no reaction occurs between acidified hydrogen peroxide and halide ions other than iodide?
No reaction occurs between the acidified hydrogen peroxide and the other halide ions, because the hydrogen ions involved in both cases are in the same group. For a reaction to occur it needed to have an element that is more reactive than hydrogen.
Why tertiary alkyl halides do not undergo wurtz reaction?
Tertiary alkyl halides do not undergo the Wurtz reaction because they do not have any active hydrogen atoms that can participate in the radical coupling step. Without an active hydrogen, the radical mechanism required for the Wurtz reaction cannot proceed.
Why alkyl halides give alcohol with aqueous KOH whereas wit alcoholic KOH they give alkenes?
Alkyl halides undergo an E2 elimination reaction with alcoholic KOH to form alkenes due to the basicity of KOH in an alcohol solvent. However, with aqueous KOH, alkyl halides undergo an SN2 substitution reaction to form alcohols. The solvents play a significant role in determining the type of reaction that occurs.
Why alkyl halides undergo elimination reaction?
Alkyl halides undergo elimination reactions, such as E2 and E1, to form alkenes and hydrogen halides. This occurs in the presence of a base or nucleophile due to the tendency of the halide to leave, resulting in the formation of a double bond. The presence of a strong base favors elimination over substitution reactions.
Aryl halide do not undergo SN reaction?
Due to the bulky nature of the aryl group, aryl halides do not undergo SN reactions easily. Additionally, the carbon-halogen bond in aryl halides is strengthened due to resonance stabilization, making it more difficult for nucleophiles to displace the halogen atom. This results in aryl halides being more prone to undergo elimination reactions (E1 and E2) instead of substitution reactions.
Why furan do not show nucleophilic subtitution reaction?
Furan does not typically undergo nucleophilic substitution reactions because of its aromatic nature, which offers stability due to delocalization of the pi electrons in the ring. This makes furan less reactive towards nucleophilic attack compared to non-aromatic compounds.
Why halides of carbon do not undergo hydrolysis?
Halides of carbon, such as alkyl halides, do not undergo hydrolysis easily because they are generally stable and do not readily react with water. The carbon-halogen bond is relatively strong, and the presence of the halogen atom makes the carbon less electrophilic, reducing its reactivity towards nucleophiles like water. Additionally, the hydrolysis of carbon halides would require a significant energy input to break the carbon-halogen bond, making the reaction unfavorable under typical conditions.
What are the chemical properties of diazonium salts?
They can undergo subtitution reactions easily to form halogenated products. Submitted by pharm ajar
What will react in Nal in acetone the fastest?
In a reaction involving sodium amide (NaNH₂) in acetone, primary alkyl halides will typically react the fastest. This is due to their ability to undergo nucleophilic substitution reactions more readily than secondary or tertiary alkyl halides. The polar aprotic solvent acetone enhances the nucleophilicity of the amide ion, facilitating a quicker reaction with primary substrates.
Why alkyl halides undergoSN reactions or elimination reactins in priority?
Alkyl halides undergo both nucleophilic substituions reactions and Elimination reractions depending upon the conditions...In the presence they undergo Elimination Reactions , while in the presence of nucleophile they undergo SN reactions...By: Farman ullah ,Azim kala, masha mansoor, lakki marwat, kpk,Pakistan+92321-9632344
Is it possible for an alkyl halide to undergo sn1 and also sn2 reactions?
Yes an alkyl halide can undergo both Sn1 and Sn2 reactions - it just depends on what kind of alkyl halide it is. Methyl halides such as CH3Br/CH3Cl/CH3I, etc. are most suitable for Sn2 reactions because they are less sterically hindered by R-groups (they are not "bulky"). This allows for easy attack by the nucleophile. Primary alkyl halides (RCH2X) are also most suitable for Sn2 because of the same reason above Secondary alkyl halides can undergo both Sn1 and Sn2 reactions, this depends on other factors such as solvent and leaving group and nucleophile. If the solvent is polar aprotic, the reaction will go Sn2, if polar protic - Sn1. Tertiary alkyl halides (alkyl halides with 4 r-groups) do not go Sn2 because they are bulky and the R-groups stabilize the carbocation by hyperconjugation and inductive effect.
Why is the Sn2 pathway disfavored with aryl halides?
The SN2 pathway is disfavored with aryl halides due to the steric hindrance and the resonance stabilization of the aryl ring. Aryl halides have a planar structure that makes it difficult for the nucleophile to approach the carbon atom bonded to the halide, hindering the backside attack necessary for the SN2 mechanism. Additionally, the resonance of the aryl ring can delocalize the negative charge that would form during the transition state, making the reaction less favorable. Therefore, aryl halides typically undergo alternative mechanisms, such as nucleophilic aromatic substitution (SNAr).
Why primary alkyl halide are not syntesized using Sn1 reaction?
as order of reactivity of sn1 reaction is 3>2>1 , we do not synthesise primary alkyl halide using sn1 reation. as there is no pushing from other carbon atoms, it is difficult for the X part of RX to separate itself.
