this is simply by the energy needed for the outer electron of boron is less than the energy for carbons outer electron. most elements which change shell will have a sudden decrease which then the factor of extra shielding decreases the attraction of the electron and the center of the atom.
becasue when you remove a second elctron from Boron you are entering a new sublevel, the 2s sublevel, which already contains 2 electrons and is in a stable form, where as when you are removing a second electron from carbon it is still in the same energy sublevel, the 2p sublevel so it requires less energy
Boron has 5 protons in the nucleus and Carbon has 6 protons in the nucleus. These hold the electrons in place, and since both have electrons in the 2nd energy level (period 2), the electrons are the same distance from the nucleus. So, it will be harder to remove an electron from carbon than from boron, because of the greater attraction by the nucleus. Thus a higher ionization energy.
because if krypton has more protons, therefore it has a greater nuclear charge so the electron is harder to remove
It isn't. The ionization potential of boron is 8.2980 eV, and the ionization potential of carbon is 11.2603 eV.
Beryllium is the group 3A element with the highest ionization energy.
There are two main elements that do not follow the trend for ionization energy. Those two elements are both Boron and Oxygen.
The maximum capacity of electron accommodation in aluminium is 18 electrons( M shell) on contraty it has only 3 valence electrons whereas boron has maximum capacity of 8 electrons(L shell) and it has 3 valence electrons so electron population of Aluminium is less than that of boron.
Boron is unique because it is the only nonmetallic element found in Group 13 of the periodic table. It has a small atomic size and a high ionization energy, making it ideal for use in various applications such as energy-efficient materials, high-strength alloys, and neutron radiation shielding. Boron also exhibits interesting properties like its ability to form stable compounds with carbon (boron carbide) and its role in plant growth as an essential micronutrient.
Boron and carbon are not similar but both are nonmetals.
Carbon has the highest ionization energy
Oxygen
Across a row on the periodic table ionization energy increases. Down a column, ionization energy decreases. --------------------------------------------------------- The first Ionization energy of Boron is 800.6 kJ mol-1
Because fluorine's size is lower than that of iodine, it has a greater ionization energy than iodine. Fluorine, on the other hand, appears to have a smaller shielding effect. As a result, fluorine's nucleus attracts more valence electrons than iodine's.
Beryllium is the group 3A element with the highest ionization energy.
Ionization energy generally increases across a period as a result of a higher nuclear charge, however there are some exceptions such as Boron which has a lower ionization energy than Beryllium (because it is in a P orbital), and Oxygen which has a lower ionization energy than nitrogen (Because ionization decreases the electron electron repulsion in its orbitals).
Lithium
lithium
boron
There are two main elements that do not follow the trend for ionization energy. Those two elements are both Boron and Oxygen.
Because in Boron there is a complete 2s orbital and the increased shielding of the 2s orbital reduces the ionisation energy compared to that seen in Beryllium.
In the periodic table of elements, fluorine and iodine are in the same column, but fluorine is in the second, iodine in the fifth row. That means fluorine has only nine electrons flying around in orbitals while iodine has 53 of them. Ionization is the called a process during which a single electron is abstracted - we're now talking about the 1st ionization energy, which is much higher for fluorine. Well, as it only has nine electrons scattered in the orbitals (but according laws, of course), they do not really influence the repelling - attracting actions between the positive center and the other electrons beside them. For iodine with 53 electrons, they really do interfere with the attraction of other electrons AND as the outmost electrons (which are the ones taken away by ionization) are in those orbitals which are at the biggest distance to the center - for 53 electrons the outmost orbitals is at a much bigger distance... both results in a smaller attraction of the electrions at max distance from the center... so for iodine you need less energy to perform ionization.