P and S both have 'd' orbitals in outermost shell while N and O do not.
Elements in the third row of the periodic table or lower can have octets in their outermost electron shell due to the availability of d orbitals for bonding. This allows them to exceed the usual octet rule of 8 electrons in their valence shell. Examples include elements like sulfur, phosphorus, and chlorine.
The second row nonmetals that can form electron deficient compounds are boron and carbon. Boron tends to form electron deficient compounds by having incomplete octets, while carbon can form electron deficient compounds like carbocations in certain chemical reactions.
The Lewis structure for NSF (nitrogen sulfide fluoride) has nitrogen as the central atom with one nitrogen-sulfur single bond and one nitrogen-fluorine single bond. Nitrogen has one lone pair of electrons and follows the octet rule, while sulfur and fluorine both have complete octets.
Yes, SeO2F2 and ONF3 contain atoms with expanded octets. In SeO2F2, the selenium atom has 12 electrons around it, exceeding the octet. In ONF3, the nitrogen atom has 10 electrons around it, also exceeding the octet. However, GaCl3 does not have any atoms with expanded octets as gallium follows the octet rule.
The question cannot be answered sensibly because it is based on the misconception that compounds of xenon such as its difluoride, tetrafuoride, hexafluoride, tetroxide, and so on do not exist!
Elements in the third period or beyond (Si and beyond) in the periodic table can form compounds with expanded octets. This includes elements such as sulfur, phosphorus, chlorine, and xenon. These elements can often exceed the octet rule by forming more than 8 electrons in their valence shell in some compounds.
maximum 60 octets minimum 20 octets
Nitrogen and bromine will form a covalent bond. Nitrogen typically forms three covalent bonds, while bromine forms one covalent bond. When they combine, they will share electrons to complete their octets.
Elements in the third row of the periodic table or lower can have octets in their outermost electron shell due to the availability of d orbitals for bonding. This allows them to exceed the usual octet rule of 8 electrons in their valence shell. Examples include elements like sulfur, phosphorus, and chlorine.
The second row nonmetals that can form electron deficient compounds are boron and carbon. Boron tends to form electron deficient compounds by having incomplete octets, while carbon can form electron deficient compounds like carbocations in certain chemical reactions.
To provide an accurate answer, I would need to see the specific context or content of the highlighted octets you're referring to. Please provide the octets or additional details, and I'll be happy to help!
Octets do.
The Lewis structure for NSF (nitrogen sulfide fluoride) has nitrogen as the central atom with one nitrogen-sulfur single bond and one nitrogen-fluorine single bond. Nitrogen has one lone pair of electrons and follows the octet rule, while sulfur and fluorine both have complete octets.
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Yes, SeO2F2 and ONF3 contain atoms with expanded octets. In SeO2F2, the selenium atom has 12 electrons around it, exceeding the octet. In ONF3, the nitrogen atom has 10 electrons around it, also exceeding the octet. However, GaCl3 does not have any atoms with expanded octets as gallium follows the octet rule.