NaOH is a strong base so it abstracts the proton from p-nitrophenol resulting in the formation of p-nitrophenoxide ion and water, but HCl is a strong acid so its conjugate base (Chloride ion) if in-case abstracts the proton from p-nitrophenol the resulting p-nitrophenoxide will accept the proton released from acid and again changes into p-nitrophenol, so there will not be any effect. Simply p-nitrophenol is also a weak acid & there will not be any reaction of it with strong hydrochloric acid.
p-nitrophenol does not reac with HCl but with NaOH it forms salt,
O2N-C6H4-OH + NaOH = O2N-C6H4-O-Na+ + H2O
When HCl and NaOH react common salt (NaCl) is formed .This reaction is also called neutralization reaction .
No, neither, niente, noppa, zero
Because it has no functional groups, its a very stable compound.
There will be no reaction of Hexane as it does'nt have any reactive sites. Hexene will react only with Hcl as the double bond is nucleophilic to give poly chlorinated hexane. Hexene will not react with NaOH
NaOH and HCl
When HCl and NaOH react common salt (NaCl) is formed .This reaction is also called neutralization reaction .
No, neither, niente, noppa, zero
Because it has no functional groups, its a very stable compound.
NaOH and HCl
The reaction is: NaOH + HCl = NaCl + H2O HCl and NaCl cannot react, the anion is the same.
There will be no reaction of Hexane as it does'nt have any reactive sites. Hexene will react only with Hcl as the double bond is nucleophilic to give poly chlorinated hexane. Hexene will not react with NaOH
These chemicals react in a direct proportion of one to one, measured in moles of course, not by weight. A mole of NaOH weighs more than a mole of HCl.
Try sodium hydroxide. NaOH + HCl >> NaCl + H2O
The product is sodium chloride.The reaction is:NaOH + HCl - NaCl + H2O
The equation involved is a neutralization reaction. HCl + NaOH -> NaCl + H2O In this reaction, acid and base react to produce a salt.
NaOH + HCl >> NaCl + H2O A salt and water produced.
Sodium hydroxide in a pure form is a solid, so you cannot dissolve anything in it. Normally, NaOH is used as an aqueous solution. But salicylic acid dissolves in water, so the presence of NaOH in the water is irrelevant to the solubility of salicylic acid. It is the water, not the NaOH, that dissolves the salicylic acid.