An electrolysis process is based upon movement and flow of ions. More is the solution dilute, more is the movement of ions and more is the conductance of solution.
Thus, when the solution is dilute more copper ions flow to the electrode and get deposited
there
If you want to extract copper using dilute acid you must use sulphuric dilute acid. Pour it into a container and add some copper oxide (it's powder, I'm not sure if that's it's name) then take another container and put some filter paper on it and pour the mixture into that. It should look blue. Then add some filings into it and they should turn pink.
Usually hydrogen will evolve from the cathode and oxygen from the anode, but if zinc is the anode, it may dissolve to produce zinc ions in the solution either instead of or along with oxygen evolving.
You would add powdered copper carbonate to dilute hydrochloric acid to produce copper chloride solution and carbon dioxide gas.
right i dont know this 4 sure but because u want a 0.1 mol/dm3 and u only need 100cm3 u will need 0.01mols of copper sulfate to dilute in 100cm3. soo now u have a solution that is 0.01mols per 100cm3 or 0.1 mols per 1000cm3 (dm3)
Copper(II) hydroxide can be produced by adding a small amount of sodium hydroxide to a dilute solution of copper(II) sulfate (CuSO4 · 5H2O). The precipitate produced in this manner, however, often contains water molecules and an appreciable amount of sodium hydroxide impurity. A purer product can be attained if ammonium chloride is added to the solution beforehand. Alternatively, copper hydroxide is readily made by electrolysis of water (containing a little electrolyte such as sodium bicarbonate). A copper anode is used, often made from scrap copper.
If you want to extract copper using dilute acid you must use sulphuric dilute acid. Pour it into a container and add some copper oxide (it's powder, I'm not sure if that's it's name) then take another container and put some filter paper on it and pour the mixture into that. It should look blue. Then add some filings into it and they should turn pink.
Usually hydrogen will evolve from the cathode and oxygen from the anode, but if zinc is the anode, it may dissolve to produce zinc ions in the solution either instead of or along with oxygen evolving.
You would add powdered copper carbonate to dilute hydrochloric acid to produce copper chloride solution and carbon dioxide gas.
Blue
Mixing these two reagents would make a dilute solution of copper sulfate.
Well, friend, to dilute 1 liter of a copper chloride solution from 100,000 ppm to 1 ppm, you'll need to add quite a bit of water. You see, for every liter of the original solution, you'll need to add 99 liters of water. This will help bring the concentration down to that lovely 1 ppm you're aiming for. Just remember to mix it all up gently, like you're painting a beautiful sky.
A very dilute solution of copper sulfate is used in the biuret test because it allows for the detection of proteins through the formation of a complex with peptide bonds. When proteins are present, the copper ions in the dilute solution react with the peptide bonds, resulting in a color change to violet. The dilution ensures that the solution is not too concentrated, which could lead to interference in color interpretation and false positives. This sensitivity is crucial for accurately determining protein presence in a sample.
The acid that reacts with copper(II) carbonate to give a blue solution is hydrochloric acid (HCl). This reaction forms a solution of copper(II) chloride, which appears blue due to the presence of copper ions.
Probably a very dilute solution of copper sulphate act as a desinfecting agent; but the copper sulphate is toxic. It is more sure to avoid this experiment.
Oh, dude, you'd need a lot of water for that. Like, a crazy amount. To dilute copper chloride solution from 100000 ppm to less than 1 ppm, you'd need to dilute it by a factor of 100000. So, you'd need to add 99999 parts water for every part of the original solution. Good luck with that math!
Copper does not react with dilute Sulphuric acid.
The dilute solution become a concentrated solution.