It is neutral because it is the salt of a strong acid (HI) and a strong base (KOH). Thus, when it hydrolyzes, it forms KOH and HI, a neutral solution.
KI (potassium iodide) is a salt that dissociates into K+ and I- ions in water. Both potassium ions and iodide ions are neutral and do not affect the pH of a solution. Therefore, the pH of a solution of KI would remain unchanged.
It is neutral.
55 ml of a 4.05 M solution of KI solution contains 55*4.05=222.75 millimoles. 20.5 ml of the diluted solution contains 3.8g of KI,so no.of moles of KI=3.8/(mol.wt of KI=165.9) is 22.9 millimoles. molarity of final diluted solution=22.9/20.5=1.117M since the no. of moles of KI present in initial and final solution are same. let.V(in ml) be the final volume of diluted solution. 222.75/V=1.117 V=199.41 ml final volume =199.41 ml
Neutral
Sodium nitrate (NaNO3) is a neutral salt. When dissolved in water, it will not significantly affect the pH of the solution.
KI (potassium iodide) is a salt that dissociates into K+ and I- ions in water. Both potassium ions and iodide ions are neutral and do not affect the pH of a solution. Therefore, the pH of a solution of KI would remain unchanged.
It is neutral.
To make a 10% KI solution, dissolve 10 grams of potassium iodide (KI) in 90 grams of water, for a total of 100 grams of solution. This will give you a 10% weight/volume (w/v) solution of KI.
A neutral solution is a solution that has a pH level of seven. Pure water is an example of a neutral solution.
The PH neutral solution in sciences is 7 and neutral is green.
A neutral solution is true neutral with a pH of 7,00.
Neutral in what sense? Guessing pH a neutral solution has a pH of 7.
Ultrapure water is a neutral solution.
No milk is not a neutral solution
It is neutral.
Sodium chloride solution in water is neutral.
To find the molarity of the potassium iodide (KI) solution, first convert the mass of KI into moles. The molar mass of KI is approximately 166 g/mol, so 11.37 mg (or 0.01137 g) corresponds to about 0.0000683 moles of KI. Next, divide the number of moles by the volume of the solution in liters (0.103 L) to find the molarity. Thus, the molarity of the KI solution is approximately 0.000663 M.