For preparation of standard solution of Mohr salt {FeSO4.(NH4)2SO4.6H2O}, it's necessary to add dilute H2SO4 to prevent the Fe2+ ions of Mohr salt solution from undergoing oxidation (to Fe3+).
Just try to prepare the standard solution without adding this acid. You'll observe that your "Mohr solution" will become yellow in colour, i.e., it won't remain "Mohr salt solution" anymore, hence can't be used in titration.
And while doing the titration of the Mohr salt solution with KMnO4 (or even with K2Cr2O7), you need to add dilute H2SO4. The reason is well explained by the chemical equation involved:
reduction: (MnO4)- + 8H+ + 5e ----> Mn2+ + 4H2O
oxidation: Fe2+ ----> Fe3+ + e
net equation:
(MnO4)- + 8H+ + 5Fe2+ ----> Mn2+ + 4H2O + 5Fe3+
There is involvement of H+ ions in this reaction. This redox titration requires acidic medium. Moreover, KMnO4 acts as a very good oxidizing agent in the presence of acidic medium, than in the basic and neutral medium.
NOTE: Now a query may arise that for providing acidic medium, can HCl or HNO3 be used? (Let me tell you it's one of the favourite questions of external examiners)
The answer is NO, because HNO3 is a very strong oxidizing agent. So, the Fe2+ present will be oxidized both by KMnO4 and HNO3, which will result in an error in determination of volume of KMnO4 reacting with Mohr salt solution.
Also, HCl can't be used because Cl- from HCl will be oxidized by KMnO4:
HCl (aq) ---> H+ (aq) +Cl- (aq)
oxidation by KMnO4=> 2Cl- ----> Cl2 + 2e
So, some extra KMnO4 will be used up because it will oxidize both- Cl- as well as Fe2+, => error in titration.
To prepare 0.25N sulphuric acid from 2N sulphuric acid, you can dilute the 2N solution by adding 7 parts of water to 1 part of the 2N solution. This will result in a final 0.25N sulphuric acid solution.
One way to convert dilute sulphuric acid to concentrated sulphuric acid is through a process called evaporation. In this method, the dilute acid is heated to evaporate the water content, leaving behind the concentrated acid. Another method involves adding concentrated sulphuric acid to the dilute solution until the desired concentration is achieved.
When silver metal is added to dilute sulphuric acid solution, a redox reaction takes place. The silver metal reacts with the sulfuric acid to produce silver sulfate and hydrogen gas. The reaction can be represented by the following equation: 2Ag(s) + H2SO4(aq) -> Ag2SO4(aq) + H2(g)
When copper reacts with dilute sulphuric acid, copper sulfate and hydrogen gas are produced. The copper sulfate formed will be a blue solution. This reaction is a redox reaction, where copper is oxidized and hydrogen is reduced.
2N dilute sulfuric acid refers to a solution where the concentration of sulfuric acid (H2SO4) is equivalent to 2 moles per liter (2N). This solution is often used in chemical reactions or laboratory experiments that require a specific concentration of sulfuric acid.
No. It is a mixture of sulphuric acid and water.
To prepare 0.25N sulphuric acid from 2N sulphuric acid, you can dilute the 2N solution by adding 7 parts of water to 1 part of the 2N solution. This will result in a final 0.25N sulphuric acid solution.
Yes, it is dilute sulphuric acid.
One way to convert dilute sulphuric acid to concentrated sulphuric acid is through a process called evaporation. In this method, the dilute acid is heated to evaporate the water content, leaving behind the concentrated acid. Another method involves adding concentrated sulphuric acid to the dilute solution until the desired concentration is achieved.
H2SO4(dilute)
Colorless. The resulting solution is zinc sulfate, and Zn2+ ions are colorless.
the answer is dilute sulphuric acid... thats what everyone says
When silver metal is added to dilute sulphuric acid solution, a redox reaction takes place. The silver metal reacts with the sulfuric acid to produce silver sulfate and hydrogen gas. The reaction can be represented by the following equation: 2Ag(s) + H2SO4(aq) -> Ag2SO4(aq) + H2(g)
When copper reacts with dilute sulphuric acid, copper sulfate and hydrogen gas are produced. The copper sulfate formed will be a blue solution. This reaction is a redox reaction, where copper is oxidized and hydrogen is reduced.
irritant
Copper does not react with dilute Sulphuric acid.
For preparation of standard solution of Mohr salt {FeSO4.(NH4)2SO4.6H2O}, it's necessary to add dilute H2SO4 to prevent the Fe2+ ions of Mohr salt solution from undergoing oxidation (to Fe3+).