sulphuric acid is a diprotic acid so has two H+ and needs two moles of sulphuric acid to neutralise it
Yes, the reaction involving the solid is actually an individual step in the equation of the reaction between the solutions. If you were to add the change in enthalpy of the reaction with the solid NaOh to the change in enthalpy of the other step in the reaction (that's adding water and the NaOh pellets) you would find the sum equivalent to the change in enthalpy of the reaction involving the two solutions (this is supported by Hess's law). I suggest that you consider Hess's law for more information.
The reaction between iron hydroxide and hydrochloric acid is a chemical reaction because it involves a rearrangement of atoms to form new substances with different properties. The iron hydroxide reacts with the hydrochloric acid to form iron chloride and water.
it is always water.
When copper hydroxide reacts with hydrochloric acid, it forms copper chloride and water. This reaction involves the exchange of ions between the copper hydroxide and the hydrochloric acid.
in my chem 201 lab we found this to be 1.099 kJ/ mol. I am in fact looking for the accepted value as well. So i assume my result is near the accepted i hope. If anyone knows throw down your info.
Yes, the reaction involving the solid is actually an individual step in the equation of the reaction between the solutions. If you were to add the change in enthalpy of the reaction with the solid NaOh to the change in enthalpy of the other step in the reaction (that's adding water and the NaOh pellets) you would find the sum equivalent to the change in enthalpy of the reaction involving the two solutions (this is supported by Hess's law). I suggest that you consider Hess's law for more information.
The reaction between iron hydroxide and hydrochloric acid is a chemical reaction because it involves a rearrangement of atoms to form new substances with different properties. The iron hydroxide reacts with the hydrochloric acid to form iron chloride and water.
it is always water.
When copper hydroxide reacts with hydrochloric acid, it forms copper chloride and water. This reaction involves the exchange of ions between the copper hydroxide and the hydrochloric acid.
in my chem 201 lab we found this to be 1.099 kJ/ mol. I am in fact looking for the accepted value as well. So i assume my result is near the accepted i hope. If anyone knows throw down your info.
alkaline
The reaction is:HCl + NaOH = NaCl + H2O
Yes, the reaction of hydrochloric acid with sodium hydroxide is a chemical change. It forms water and sodium chloride, which are different substances with new chemical properties compared to the reactants.
The reaction of potassium hydroxide with dilute hydrochloric acid forms potassium chloride and water. This reaction is a neutralization reaction, which involves the combining of an acid and a base to form water and a salt.
In the reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl), the chemical compound that is used up is sodium hydroxide (NaOH), as it reacts with hydrochloric acid to form water (H2O) and sodium chloride (NaCl).
The word eq'n is:- Hydrochloric Acid + Aluminium hydroxide = Aluminium Chloride + Water. Here is the BALANCED reaction eq'n 3HCl(aq) + Al(OH)3(aq) = AlCl3(aq) + 3H2O(l)
The reaction between magnesium hydroxide and hydrochloric acid is a neutralization reaction. When these two compounds react, they form magnesium chloride and water. The hydroxide ions from the magnesium hydroxide combine with the hydrogen ions from the hydrochloric acid to form water, leaving behind magnesium chloride as the salt.