First, write the net-ionic reactions for both neutralization reactions. Notice anything?
They have the same net-ionic reaction! So, their heats of neutralization will be the same.
HNO3 + NaOH NaNO3 + H2O
The neutralization of a base, or an acid for that matter, is a chemical property, because you are reacting the base with an acid to change the base into a different compound. For example: NaOH (a strong base) + HNO3 (a strong acid) ---> NaNO3 + H2O
KOH(aq) + HNO3(aq) = KNO3(aq) + H2O(l)
Neutralization: HNO3 + NaOH -> NaNO3 + H2O Decomposition by heating: NaNO3 -> NaNO2 + 1/2 O2 Preparation of HNO2: NaNO2 + HCl -> HNO2 + NaCl
koh+ hno3>h2o+kno3
HNO3+ NaOH = NaNO3+ H2O is a neutralization reaction
HNO3 + NaOH NaNO3 + H2O
It is a neutralization reaction. An example: HNO3 + NaOH ---> NaNO3 + H2O, where HNO3 is nitric acid and NaNO3 is sodium nitrate.
The neutralization of a base, or an acid for that matter, is a chemical property, because you are reacting the base with an acid to change the base into a different compound. For example: NaOH (a strong base) + HNO3 (a strong acid) ---> NaNO3 + H2O
KOH(aq) + HNO3(aq) = KNO3(aq) + H2O(l)
Neutralization: HNO3 + NaOH -> NaNO3 + H2O Decomposition by heating: NaNO3 -> NaNO2 + 1/2 O2 Preparation of HNO2: NaNO2 + HCl -> HNO2 + NaCl
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koh+ hno3>h2o+kno3
It would be expected to be near neutral, because it is produced by reacting nitric acid (HNO3) with sodium hydroxide (NaOH). It represents the salt product of a strong acid and a strong base, so its pH in solution will be very near 7.
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
1/103.4= 4.0 x 10 -4 M HNO3==============
HCl and HNO^3 are both acids therefore Neutralisation cannot occur.