The best modern answer would involve quantum chemistry, but an easier to understand explanation is that the outermost electrons in fluorine are much closer to the nucleus that provides the attraction to hold the electrons and nucleus together as an atom than are the outermost electrons in iodine. This is sometimes called the "screening effect" of inner shell electrons that weakens the attraction between the nucleus and the outer shell electrons in large atoms such as iodine.
The ionization energy of fluorine is 1681 kJ/mol (the first) and the ionization energy of iodine is 1008,4 kJ/mol.
Fluorine has a higher charge than iodine because fluorine is more electronegative than iodine. This means that fluorine has a greater ability to attract electrons towards itself, resulting in a higher charge. Additionally, fluorine's smaller size allows it to exert a stronger pull on electrons compared to the larger iodine atom.
Yes. It's true. Chlorine has the highest electron affinity, then Fluorine, Bromine and Iodine
On the periodic table, the symbol for iodine is I and the symbol for fluorine is F.
Iodine is the biggest atom among bromine, fluorine, chlorine and iodine as it has the highest atomic number and atomic radius.
The ionization energy of fluorine is 1681 kJ/mol (the first) and the ionization energy of iodine is 1008,4 kJ/mol.
Fluorine has a higher charge than iodine because fluorine is more electronegative than iodine. This means that fluorine has a greater ability to attract electrons towards itself, resulting in a higher charge. Additionally, fluorine's smaller size allows it to exert a stronger pull on electrons compared to the larger iodine atom.
Because fluorine's size is lower than that of iodine, it has a greater ionization energy than iodine. Fluorine, on the other hand, appears to have a smaller shielding effect. As a result, fluorine's nucleus attracts more valence electrons than iodine's.
Fluorine is more reactive than iodine, so fluorine can displace iodine in a chemical reaction to form a compound. This displacement reaction occurs because fluorine has a higher electronegativity and stronger oxidizing ability than iodine.
Yes. It's true. Chlorine has the highest electron affinity, then Fluorine, Bromine and Iodine
On the periodic table, the symbol for iodine is I and the symbol for fluorine is F.
a lower molecular weight and weaker intermolecular forces compared to iodine. This results in fluorine being a gas at STP, while iodine, with its higher molecular weight and stronger intermolecular forces, exists as a solid at the same conditions.
Iodine is the biggest atom among bromine, fluorine, chlorine and iodine as it has the highest atomic number and atomic radius.
Bromine would be the least reactive out of chlorine, iodine, bromine, and fluorine. It is a nonmetal halogen that has lower reactivity compared to fluorine, chlorine, and iodine.
Fluorine has the smallest atomic radius among fluorine, chlorine, bromine, iodine, and astatine.
Fluorine has the most metallic character among fluorine, chlorine, bromine, and iodine. Metallic character decreases as you move across a period from left to right on the periodic table, and fluorine is the first element in the halogen group.
In the periodic table of elements, fluorine and iodine are in the same column, but fluorine is in the second, iodine in the fifth row. That means fluorine has only nine electrons flying around in orbitals while iodine has 53 of them. Ionization is the called a process during which a single electron is abstracted - we're now talking about the 1st ionization energy, which is much higher for fluorine. Well, as it only has nine electrons scattered in the orbitals (but according laws, of course), they do not really influence the repelling - attracting actions between the positive center and the other electrons beside them. For iodine with 53 electrons, they really do interfere with the attraction of other electrons AND as the outmost electrons (which are the ones taken away by ionization) are in those orbitals which are at the biggest distance to the center - for 53 electrons the outmost orbitals is at a much bigger distance... both results in a smaller attraction of the electrions at max distance from the center... so for iodine you need less energy to perform ionization.