The second ionization energy of oxygen is greater than fluorine because in oxygen, after the first electron is removed, the remaining electron is from a filled shell (2p^4). This electron in oxygen experiences greater electron-electron repulsion, making it harder to remove compared to the outer electron in fluorine which is in a half-filled shell (2p^5).
The electron configuration for an atom of fluorine is [He]2s2.2p5.
The elements in the second period are lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine, and neon.
The highest energy shell of Fluorine is 2nd shell which contains 7 electrons just like other halogens.
There is no third energy level of oxygen, there is only two. The second energy level has 6 electrons.
The second ionization energy for lithium is greater than the first because removing the second electron requires breaking a stronger bond due to the higher effective nuclear charge after the first electron is removed. This leads to a greater energy input to remove the second electron compared to the first.
Fluorine has the highest electronegativity among the three elements. Oxygen is the second most electronegative, while chlorine has a slightly lower electronegativity compared to both fluorine and oxygen.
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Because with the 2nd ionisation of K, you are trying to take an electron from a fully filled orbital (octet rule) whereas with calcium it is getting down to a fully filled orbital
The second energy level of an atom of fluorine will have 7 electrons. This is because the first energy level can hold a maximum of 2 electrons, and the second energy level can hold a maximum of 8 electrons. Since fluorine has a total of 9 electrons, 2 of them will be in the first energy level and 7 will be in the second energy level.
The electron configuration for an atom of fluorine is [He]2s2.2p5.
Second ionization energy of fluorine is the amount of energy needed to remove an electron from a unipositive fluorine atom (F+)to form F2+,in all the gaseous state
The elements in the second period are lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine, and neon.
Neon has a higher second ionization energy than fluorine because its first ionization energy removes an electron from a stable noble gas configuration, resulting in a very stable ion. In contrast, fluorine's second ionization energy involves removing an electron from a more unstable anion (F⁻), which is easier than removing a second electron from neon's filled outer shell. Additionally, the effective nuclear charge experienced by the remaining electrons in neon is higher, making it more difficult to remove the second electron compared to fluorine.
Fluorine's atomic radius is smaller than that of chlorine but larger than that of oxygen. This trend is due to the increasing number of electron shells: fluorine and oxygen are in the second period, while chlorine is in the third. Consequently, fluorine has a greater effective nuclear charge compared to oxygen, pulling its electrons closer, while chlorine has additional electron shells, leading to a larger radius. Thus, the order of atomic radius from smallest to largest is: fluorine < oxygen < chlorine.
Fluorine has 9 electrons. The first energy level holds 2 electrons, and the second energy level holds 7 electrons. The Bohr model for fluorine would show 2 electrons in the first energy level and 7 electrons in the second energy level.
The highest energy shell of Fluorine is 2nd shell which contains 7 electrons just like other halogens.
There is no third energy level of oxygen, there is only two. The second energy level has 6 electrons.