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What is the vant Hoff factor of MgSO4 for Ki solution at a freezing-point depression of a 0.100 m MgSO4 in 0.225 Celsius?
dt = kf(im) 0.225 = kf(2(0.100m) 0.225 = kf(0.2) 0.225/0.2 = [kf(0.2)]/0.2 1.125 = kf
Why we use dst for determination of factor in kf?
its very stable
What is the molarity of KF solution containing 116 g of KF in 1.00 L?
The molarity of KF solution containing 116 g of KF in 1.00 L is 2.00 moles.
What is three ionic compound?
four properties of ionic compound are: 1-All ionic compounds form crystals 2-Ionic compounds are very hard and very brittle 3-Ionic compounds conduct electricity when they dissolve in water 4-Ionic compounds tend to have high melting and boiling points and 3 ionic compounds are: Sodium Chloride - Na Cl Potassium Fluoride - KF Magnesium Chloride - MgCl2
What is chemical composition of kf reagent?
What is the chemical composition of kf reagent
Why the melting point of potassium fluoride is higher than the melting point of potassium iodide?
KF has small size than KCl. So the packing of atoms / ions in KF is more than that in KCl. So a larger energy is needed to separate the atoms from solid state to liquid state and hence KF has higher melting point than KCl.
Why KCl or KF is added in the electrolysis of molten NaCl?
To decrease melting point of NaCl
What is happening with kf?
Kf stands for the freezing point constant of the solvent.
what- EJ, KF?
point H
What is the vant Hoff factor of MgSO4 for Ki solution at a freezing-point depression of a 0.100 m MgSO4 in 0.225 Celsius?
dt = kf(im) 0.225 = kf(2(0.100m) 0.225 = kf(0.2) 0.225/0.2 = [kf(0.2)]/0.2 1.125 = kf
What is K F?
The alphabet!The corret answer is alpha,beta,chi,delta,epsilon, gama,iota,kapa,lamdamunuomeaga pi sigma theta or tau and zeda
Why we use dst for determination of factor in kf?
its very stable
What are the six principles of management?
The KF is greater than the sum of its partsOwnership of the KF is dispersedPower in the KF flows down…and upThe KF is held together by reputation, not controlThe KF runs on information technologyThe KF is a business
How do you solve 5.167 equals log Kf How to find the value of Kf?
If log(Kf) = 5.167 then Kf = 105.167 = 146,983 (approx).
How does changing the concentration of a solution affect the kf?
Increasing the concentration of a solute the freezing point depression is increased.
What is the molarity of KF solution containing 116 g of KF in 1.00 L?
The molarity of KF solution containing 116 g of KF in 1.00 L is 2.00 moles.
How does the type of metal affect the melting of ice?
Its not exactly the metal but the metallic salt in general. in general chemistry, the van't hoff factor for that compound will affect the rate at which the melting point of the ice will decrease. the salts, such as calcium chloride, lower the melting point of ice by a certain degree related to its specific van't hoff factor. usually, a common trick is to use the number of atoms involved in the salt to approximate its factor. For example, calcium chloride, or CaCl2, has three atoms in it. So its factor is about three. This is all related to freezing point depression (courtesy of wikipedia):ΔTf = Kf · mB where * ΔTf, the freezing point depression, is defined as Tf (pure solvent) − Tf (solution), the difference between the freezing point of the pure solvent and the solution. It is defined to assume positive values when the freezing point depression takes place. * Kf, the cryoscopic constant, which is dependent on the properties of the solvent. It can be calculated as Kf = RTm2M/ΔHf, where R is the gas constant, Tm is the melting point of the pure solvent in kelvin, M is the molar mass of the solvent, and ΔHf is the heat of fusion per mole of the solvent. * mB is the molality of the solution, calculated by taking dissociation into account since the freezing point depression is a colligative property, dependent on the number of particles in solution. This is most easily done by using the van 't Hoff factor i as mB = msolute · i. The factor i accounts for the number of individual particles (typically ions) formed by a compound in solution.
