moloecules that do not follow the octet rule will seek to have more than a full octet.
The reason why some of these compounds exhibit paramagnitisim is due to the intrinsic nature of paramagnatisim.
Substances that have one unpaired electron are paramagnetic and those with no unpaired electrons are diamagnetic.
So a substance with 9 electrons is likely to be paramagnetic and those with even numbers are likely to be diamagnetic.
To tell if a compound is dia or para magnetic it is advisable to draw its structure and count the electrons and then place the electrons into a crystal field stabilisation enetgy diagram(C.F.S.E.) following the rules for the ligands(high/low spin, separation energy, spectrochemical series) this will give you the C.F.S.E. in bhor magnatons and if the molecule is diamagnetic or paramagnetic.
Yes, the compound P2F4 does exhibit an expanded octet.
Boron and fluorine in the trivalent boron compound BF3 have only 6 electrons in the valence shell.Oxygen and nitrogen in nitric oxide, NO, contain one or more atoms which have an odd number (one UNpaired '.' ) of electrons. Lewis dot structure |N.=O
BCl3 and BEH2 obey the octet rule because Boron and Beryllium are exceptions to the octet rule and can have stable electron configurations with less than 8 electrons. Cl3CF, NO, and SbF5 do not obey the octet rule because they have incomplete or expanded valence shells.
The elements in period 3 and above have d orbitals available for bonding which makes the "expansion" of the octet more likely. period 2 elements do not, the 2d shell has only s and p orbitals. P is in period 3, an example is PCl5 with 5 electron pairs. Se in period 4 can also expand its octet, an example is SeF6, with 6 electron pairs.
I think two elements that does not follow the octet rule are boron and beryllium. These elements always have one electron pair less than normal configuration. Boron is an important element for our body.
Yes, the compound P2F4 does exhibit an expanded octet.
No but apples do!
It is one of many, many exceptions to the octet rule. Hydrogen does NOT require 8 electrons.
Boron and fluorine in the trivalent boron compound BF3 have only 6 electrons in the valence shell.Oxygen and nitrogen in nitric oxide, NO, contain one or more atoms which have an odd number (one UNpaired '.' ) of electrons. Lewis dot structure |N.=O
No, the octet rule is a guideline, but there are exceptions for certain molecules and ions where atoms may have more or fewer than eight electrons in their valence shell. These exceptions typically involve elements from period 3 and below and can include expanded octets, odd-electron species, and species with incomplete octets.
The octet rule cannot be satisfied in molecules whose total number of valence electrons is an odd number.There are also molecules in which an atom has fewer, or more, than an octet of valence electrons.
BCl3 and BEH2 obey the octet rule because Boron and Beryllium are exceptions to the octet rule and can have stable electron configurations with less than 8 electrons. Cl3CF, NO, and SbF5 do not obey the octet rule because they have incomplete or expanded valence shells.
F2ccf2
The elements in period 3 and above have d orbitals available for bonding which makes the "expansion" of the octet more likely. period 2 elements do not, the 2d shell has only s and p orbitals. P is in period 3, an example is PCl5 with 5 electron pairs. Se in period 4 can also expand its octet, an example is SeF6, with 6 electron pairs.
I think two elements that does not follow the octet rule are boron and beryllium. These elements always have one electron pair less than normal configuration. Boron is an important element for our body.
its called an octet
Yes. Hydrogen follows the duet rule, and boron and a few other elements are exceptions. Also, the noble gases can have expanded valence levels with more than eight electrons, though they only bond under certain conditions.