The reaction belongs to a class called "single displacement" reactions. In this particular reaction, fluorine replaces the less electronegative bromine in the salt to produce free bromine and sodium fluoride according to the chemical equation:
2 NaBr + F2 -> 2 NaF + Br2.
Sodium bromide(NaBr) is formed
Yes: Bromine reacts with sodium to form sodium bromide.
The chemical reaction is:HBr + NaOH = NaBr + H2O
NaOH (aq) + HBr (aq) --> H2O (l) + NaBr (aq)
NaF :)
Sodium bromide(NaBr) is formed
The chemical reaction is: 2NaBr + F2 = 2NaF + Br2
Yes: Bromine reacts with sodium to form sodium bromide.
The chemical reaction is:HBr + NaOH = NaBr + H2O
NaOH (aq) + HBr (aq) --> H2O (l) + NaBr (aq)
Sodium Flouride (NaF) :)
Sodium Bromide is produced from the reaction of Hydrobromic acid and sodium hydroxide.
NaF :)
By Wurtz reaction of ethyl bromide with sodium metal.
no
copper bromide + sodium Hydroxide = Copper Hydroxide + Sodium Bromide CuBr2 + 2NaOH = Cu (OH)2 + 2NaBr
This is a double displacement reaction.