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An acid solution is 0.120 m in hcl and 210 m in h2so4 what volume of a 150 m koh solution would have to be added to 500.0 ml of the acidic solution to neutralize completely all of the acid?
To find the volume of KOH solution needed to neutralize the acidic solution, you'll need to determine the moles of acid present and use the stoichiometry of the neutralization reaction. Calculate the moles of HCl and H2SO4 separately, and then find the limiting reactant. Finally, use the balanced chemical equation to determine the moles of KOH needed, which can then be converted to volume using the concentration of the KOH solution.
Does an alkali easily neutralize a concentrated acid or a dilute acid?
Alkalies can neutralize both concentrated and dilute acids, but dilute acids are 'more easily' neutralized (i.e. require a smaller amount of alkali for the same amount of acid). It is a simple chemical reaction, the amount of alkali required to neutralize an acid can be calculated if you know how they react and the strengths of the acid and alkali. E.g. if you use Potassium Hydroxide (KOH) to neutralize Hydrochloric acid (HCL) the reaction is: KOH + HCL --) KCL + H2O So one molecule of KOH neutralizes one molecule of HCL If you have 1 molar KOH, then : 10 ml of dilute HCL (0.1 molar strength) will be neutralized by 1 ml of KOH 10 ml of a strong HCL (10 molar strength) will be neutralized by 100 ml of KOH Hope that helps.
What mass of potassium hydroxide is required to react completely with 2.70 g of sulfuric acid to produce potassium sulfate and water?
The balanced chemical equation for the reaction is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O From the equation, it can be seen that 2 moles of KOH react with 1 mole of H2SO4. Calculate the moles of H2SO4 (2.70 g / molar mass of H2SO4) and then use the mole ratio to find the moles of KOH required. Finally, convert the moles of KOH to mass (moles of KOH x molar mass of KOH) to get the required mass of KOH.
What is the balanced equation for phosphoric acid and potassium hydroxide?
When solving this type of problem, first use the ion charges to predict the formulas of the products. Then use coefficients to balance the equation. H3PO4 (aq) + 3 KOH (aq) --> K3PO4 (aq) + 3 H2O (l)
What is the concentration of a nitric acid solution if a 10.00 mL sample of the acid requires 31.25 mL of 0.135 M KOH for neutralization?
In an acid-base titration problem, the formula to use is: MaVa = MbVb, where the molarity of the acid times its volume equals the molarity of the base times its volume.Here, we have:Ma(10.00mL) = (0.135M)(31.25mL)Solving for Ma = 4.22M.mL / 10.00mL = 0.422M(Note: This is only valid for monoprotic acid with monoprotic bases only, as in this case. If it were titrated with 0.135M carbonate (CO32-) the findings need to be doubled.)
An acid solution is 0.120 m in hcl and 210 m in h2so4 what volume of a 150 m koh solution would have to be added to 500.0 ml of the acidic solution to neutralize completely all of the acid?
To find the volume of KOH solution needed to neutralize the acidic solution, you'll need to determine the moles of acid present and use the stoichiometry of the neutralization reaction. Calculate the moles of HCl and H2SO4 separately, and then find the limiting reactant. Finally, use the balanced chemical equation to determine the moles of KOH needed, which can then be converted to volume using the concentration of the KOH solution.
Does an alkali easily neutralize a concentrated acid or a dilute acid?
Alkalies can neutralize both concentrated and dilute acids, but dilute acids are 'more easily' neutralized (i.e. require a smaller amount of alkali for the same amount of acid). It is a simple chemical reaction, the amount of alkali required to neutralize an acid can be calculated if you know how they react and the strengths of the acid and alkali. E.g. if you use Potassium Hydroxide (KOH) to neutralize Hydrochloric acid (HCL) the reaction is: KOH + HCL --) KCL + H2O So one molecule of KOH neutralizes one molecule of HCL If you have 1 molar KOH, then : 10 ml of dilute HCL (0.1 molar strength) will be neutralized by 1 ml of KOH 10 ml of a strong HCL (10 molar strength) will be neutralized by 100 ml of KOH Hope that helps.
Why do we use KOH in saponification reaction?
KOH is used to prepare liquid soaps.
What mass of potassium hydroxide is required to react completely with 2.70 g of sulfuric acid to produce potassium sulfate and water?
The balanced chemical equation for the reaction is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O From the equation, it can be seen that 2 moles of KOH react with 1 mole of H2SO4. Calculate the moles of H2SO4 (2.70 g / molar mass of H2SO4) and then use the mole ratio to find the moles of KOH required. Finally, convert the moles of KOH to mass (moles of KOH x molar mass of KOH) to get the required mass of KOH.
What is the balanced equation for phosphoric acid and potassium hydroxide?
When solving this type of problem, first use the ion charges to predict the formulas of the products. Then use coefficients to balance the equation. H3PO4 (aq) + 3 KOH (aq) --> K3PO4 (aq) + 3 H2O (l)
Which catalyst can we use for ethoxylation?
KOH
What is the concentration of a nitric acid solution if a 10.00 mL sample of the acid requires 31.25 mL of 0.135 M KOH for neutralization?
In an acid-base titration problem, the formula to use is: MaVa = MbVb, where the molarity of the acid times its volume equals the molarity of the base times its volume.Here, we have:Ma(10.00mL) = (0.135M)(31.25mL)Solving for Ma = 4.22M.mL / 10.00mL = 0.422M(Note: This is only valid for monoprotic acid with monoprotic bases only, as in this case. If it were titrated with 0.135M carbonate (CO32-) the findings need to be doubled.)
What is the compound that reacts with potassium to form potassium hydroxide?
Potassium Hydroxide(KOH) is a base (it is "basic"). An acid will neutralize a base. Acetic acid can be used to neutralize KOH. Baking soda is a base, so it will not work to neutralize KOH.
Use of KOH in dermatologist office?
KOH (potassium hydroxide) is used to determine if a fungal infection exists on the skin.
How many milliliters of 0.45M HCL will neutralize 25.0 ml of 1.00M KOH?
To determine the amount of acid needed to neutralize the base, we can use the formula M1V1 = M2V2, where M1 is the concentration of the acid, V1 is the volume of the acid, M2 is the concentration of the base, and V2 is the volume of the base. Plugging in the values, we get (0.45)(V1) = (1.00)(25.0). Solving for V1, we find that V1 = 55.6 ml of 0.45M HCl is needed to neutralize 25.0 ml of 1.00M KOH.
What volume of 0.200 m hcl is required to completely neutralize 20.00 0f 0.300 m koh?
To determine the volume of HCl required to neutralize the KOH, we need to use the equation: Moles acid = Moles base. First, calculate the moles of KOH: (0.020 L) x (0.300 mol/L) = 0.006 moles KOH. Since HCl is in a 1:1 ratio with KOH, you'll need 0.006 moles of HCl. Using the concentration of HCl (0.200M), we get 0.006 moles / 0.200 mol/L = 0.030 L or 30.0 mL of HCl.
Name the reagents used for absorbing CO2 CO O2 during flue gas analysis by ORSAT method?
In the ORSAT method for flue gas analysis, the reagents used for absorbing CO2, CO, and O2 are potassium hydroxide (KOH) for CO2, cuprous chloride (CuCl) in KOH solution for CO, and pyrogallol solution for O2.
