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Because the volume of the gas remains constant.

U= Q+W

W=P⌂V

⌂V=0

so,W=0

Suppose you have a close spray can.The volume of gas within it is constant but you throw it in the fire,the volume remains the same although the temperature and internal energy as well as the pressure changes but since volume remains the same so work done is zero.

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What is the maximum amount of work that a gas can do during a constant-volume process?

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Related Questions

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