Because the volume of the gas remains constant.
U= Q+W
W=P⌂V
⌂V=0
so,W=0
Suppose you have a close spray can.The volume of gas within it is constant but you throw it in the fire,the volume remains the same although the temperature and internal energy as well as the pressure changes but since volume remains the same so work done is zero.
The maximum amount of work that a gas can do during a constant-volume process is zero, because work done by a gas is given by the formula W = PΔV and volume change (ΔV) is zero in a constant-volume process.
When an ideal gas expands in a vacuum, no work is done because there is no external pressure against which the gas can expand. In this case, the expansion is considered to be isentropic, meaning that there is no change in entropy of the system.
Temperature is constant during an isothermal process. The work done (W) is equal to the heat added (Q). The change in internal energy (ΔU) is zero for an isothermal process. The pressure can vary during an isothermal process, depending on the specific conditions.
Yes! But check your work... Perhaps half your curve is above the (say) x-axis and half is below. They could be canceling each other out. I had an integral heat solution problem last year. I got the answer '0' and thought I must've done something wrong, so I didn't hand my assignment in. Turns out it was zero all along!
The change in entropy equals zero when a process is reversible, meaning that the system and surroundings return to their original state without any net change in entropy.
In an isochoric process, the volume remains constant. Since work is defined as the force applied over a distance, and no mechanical work is performed when there is no change in volume, the work done in an isochoric process is zero.
In throttling process, work done is zero.
In an isochoric (constant volume) process, there is no change in volume, so the work done is zero. Therefore, all the heat added goes into increasing the internal energy of the system. The change in internal energy of the gas would be equal to the heat added, which in this case is 400 J.
The maximum amount of work that a gas can do during a constant-volume process is zero, because work done by a gas is given by the formula W = PΔV and volume change (ΔV) is zero in a constant-volume process.
Work Done = Force x Displacement, so if the displacement is zero, the work done will be zero. There will be no work done.
In an isothermal process, the temperature of the system remains constant. Since work done is the result of a change in energy, and the temperature does not change, there is no transfer of energy in the form of work during an isothermal process. Thus, the work done in an isothermal system is zero.
That means that no work is done.
no work will be done because force is applied but displacement is zero so no work will be done.
Zero work done
Work done is zero when force acts right angle to the direction of the motion of the body . my situation of zero work done , one day i hold many books approximately 15 after some time i feel very tired but there is a physical work done is zero because i worked against right angle . i feel actual work is done because when i holding book my muscles and blood circulate all over the body so i feel work is done. Arshad Quraishi
If the angle between the displacement and force applied is less than a right angle, then it is Positive Work done. If the angle between the displacement and the force applied is greater than a right angle then it is Negative Work done. If the displacement and force are at right angles, or either is zero, then it is Zero Work done.
The work done by the Earth on the space station over one complete orbit is zero because the gravitational force is conservative. This means that the work done in moving an object over any closed path is zero.