No, the equation provided is not balanced and does not correctly represent the mechanism by which ethane burns. The complete combustion of ethane is typically represented as C2H6 + 7/2 O2 -> 2 CO2 + 3 H2O.
The chemical formula for ethane is C2H6. When ethane burns, it reacts with oxygen to produce carbon dioxide (CO2) and water (H2O) as products. The balanced equation for the combustion of ethane is: 2C2H6 + 7O2 -> 4CO2 + 6H2O.
The balanced equation for the combustion of ethane (C2H6) is: 2C2H6 + 7O2 -> 4CO2 + 6H2O From the equation, for every 2 moles of ethane burned, 4 moles of CO2 are produced. Therefore, if 5.60 mol of ethane are burned, then (5.60 mol / 2 mol ethane) * 4 mol CO2 = 11.2 mol of CO2 are produced.
The balanced chemical equation for the combustion of ethane (C2H6) in oxygen is: 2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
Sodium propanoate (or propionate) when heated with soda lime ethane gas is produced.
Out of methane, ethane, propane, and butane, butane has the highest boiling point.
I am presuming that you are asking how many carbon dioxide (CO2) molecules will be formed when two ethane (C2H6) molecules burn in a plentiful supply of oxygen. The following balanced equation is that of the burning of ethane in a plentiful supply of oxygen: C2H6 + 3.5O2 -----> 2CO2 + 3H2O. The number before each of the molecules in the equation tells us how many there are in this reaction. This means that for every one ethane molecule that is burnt, two carbon dioxide molecules are produced.
The chemical formula for ethane is C2H6. When ethane burns, it reacts with oxygen to produce carbon dioxide (CO2) and water (H2O) as products. The balanced equation for the combustion of ethane is: 2C2H6 + 7O2 -> 4CO2 + 6H2O.
Incomplete combustion of a hydrocarbon typically produces carbon monoxide and water vapor. The word equation for incomplete combustion of ethane, for example, is: ethane + oxygen → carbon monoxide + water
The balanced equation for the combustion of ethane (C2H6) is: 2C2H6 + 7O2 -> 4CO2 + 6H2O From the equation, for every 2 moles of ethane burned, 4 moles of CO2 are produced. Therefore, if 5.60 mol of ethane are burned, then (5.60 mol / 2 mol ethane) * 4 mol CO2 = 11.2 mol of CO2 are produced.
The balanced chemical equation for the combustion of ethane (C2H6) in oxygen is: 2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
Sodium propanoate (or propionate) when heated with soda lime ethane gas is produced.
Out of methane, ethane, propane, and butane, butane has the highest boiling point.
Butane would have the highest boiling point among ethane, propane, and butane.
This equation can not be balanced with the species present. Are you sure the species are correctly written?
ethane + Oxygen --> Carbon dioxide + Water
The combustion reaction of ethane (C2H6) with oxygen produces carbon dioxide and water. The balanced equation for the combustion of ethane is: [ 2 \text{C}_2\text{H}_6 + 7 \text{O}_2 \rightarrow 4 \text{CO}_2 + 6 \text{H}_2\text{O} ] From the equation, 2 moles of ethane produce 6 moles of water. Therefore, 4 moles of ethane will produce ( \frac{6}{2} \times 4 = 12 ) moles of water.
The subscripts in the formula for ethane (C2H6) represent the number of atoms of each element in the compound. In this case, "C2" indicates there are 2 carbon atoms, and "H6" indicates there are 6 hydrogen atoms in one molecule of ethane.