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You have .2 n kmno4 which you have to dilute it to 0.05n kmno4 how can you dilute that?
Wiki User
∙ 11y ago
4 x. Take 25ml of 0.2 M solution and dilute to 100ml.
Wiki User
∙ 11y ago
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What is the chemical formula k and n?
There is no such thing as K2N. K3N is potassium nitride.
N-phenylanthranilic acid indicator how to prepare?
dilute with water
How do you prepare 0.05 N solution of KMnO4?
Dissolve 1,65 g potassium permanganate for analysis in 1 L demineralized water.
How much water is needed to dilute 10 L of 3.0 N HCl solution to 0.2 N HCl solution?
Add 5 litres water.
How can you prepare 0.02 N NaOH solution if i have .2N NaOH?
In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml
What is the chemical formula k and n?
There is no such thing as K2N. K3N is potassium nitride.
N-phenylanthranilic acid indicator how to prepare?
dilute with water
How do you prepare 0.05 N solution of KMnO4?
Dissolve 1,65 g potassium permanganate for analysis in 1 L demineralized water.
How do you prepaire 0.05N NaOH from 1N NaOH?
Dissolve 20g of NaOH in about 500 mL of water and dilute with water to 1000mL. Mix well.
How much water is needed to dilute 10 L of 3.0 N HCl solution to 0.2 N HCl solution?
Add 5 litres water.
How do you make .02 N hydrochloric acid?
dilute 1.7 ml of Conc. HCl to 1000 ml with water
Evaluate the expression f left parenthesis n plus 2 right parenthesis minus f left parenthesis n right paren given that f left paren n right paren equals 1 over 2 n left paren n plus 2 right paren?
A very good try, but f(n) is still ambiguous. I assume you mean f(n) = 1/2*n*(n+2) and not 1/[2*n*(n+2)] Then f(n+2) - f(n) = 1/2*(n+2)*(n+2+2) - 1/2*n*(n+2) = 1/2*(n+2)*(n+4) - 1/2*n*(n+2) = 1/2*(n+2)*{(n + 4) - n} = 1/2*(n+2)*4 = 2*(n+2)
How can you prepare 0.02 N NaOH solution if i have .2N NaOH?
In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml
What is n divided by 2?
It is n/2.
How do you make 6 N ammonium hydroxide?
Dilute 400ml of concentrated solution (14.8 M, 28% NH3) to 1 litre.
What is the 34th number in this sequence 2 6 12 20?
The 34th number is 1190. First number is 2 = 2n where n = 1 Second number is 4 + 2 = 2n + 2(n-1) where n = 2 Third number is 6 + 4 + 2 = 2n + 2(n-1) + 2(n -2) where n = 3 Fourth number is 8 + 6 + 4 + 2 = 2n + 2(n-1) + 2(n-2) + 2(n-3) where n = 4 . . . In general the nth number is 2n + 2(n-1) + 2(n-2) + 2(n-3) + ..... + 2(n-n+1) and In general the nth number is 2n + 2(n-1) + 2(n-2) + 2(n-3) + ..... + 2(1) Take 2 as a common factor and we get nth number = 2(n + n -1 + n -2 + n -3 + ..... + 1) which is = 2(1 + 2 + 3 + ..... + n-3 + n-2 + n-1 + n) = 2(sum of n numbers starting with 1) But sum of n numbers starting with 1 is (n)(n+1)/2 Hence nth number in general is (2)(n)(n+1)/2 = n(n+1) Hence 34th number would be 34(34+1) = 34x35 = 1190
What is the pattern 2 4 16 3 9 81 4 16 256 5 25 625?
n, n^2, n^2^2, n+1, (n+1)^2, (n+1)^2^2, n+2, ...
