ZnCl2 + NaOH --> NaCl2 + ZnOH
Zn2+ + Cl- + Na+ +OH- --> Na+ + Cl- + ZnOH
Zn+ + OH- ---> ZnOH(s)
Al2(SO4)3(s) + 6 NaOH(ac) ---> 2 Al(OH)3 (s) + 3 Na2(SO4) (ac)
NaohZnso47hohjs << ^^ WOT A RIDICULES QUESTION YOU IDIOT!
ZnI2 + 2NaOH → Zn(OH)2 + 2NaI
Zinc (II) iodide + sodium hydroxide → Zinc (II) hydroxide + sodium iodide
I don't think such a reaction will occur
No. Zn + 2HCl = ZnCl2 + H2
yes as zinc is oxidised and hydrogen is reduced
Yes it is
2NaOH + FeSO4 --> Fe(OH)2 + Na2SO4
An acid-base reaction yielding a salt and water.
Cu and ZnCl2 are being produced.
single replacment
No. Zn + 2HCl = ZnCl2 + H2
yes as zinc is oxidised and hydrogen is reduced
Yes it is
2NaOH + FeSO4 --> Fe(OH)2 + Na2SO4
P + Na(OH) + H20 = NaH2PO2 + PH3
An acid-base reaction yielding a salt and water.
The type of reaction represented by Zn plus 2NaCl yields 2Na plus ZnCl2 is an impossible one. It would be the other way around. 2Na + ZnCl2 --------> 2NaCl + Zn
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
The net ionic equation is Zn + 2H+ --> Zn2+ + H2
This equation is HCl + NaOH -> NaCl + H2O.