Required slump height of M20 for different concrete structures, are normally calculated by the required slump value, which would come out to be 100 lits.
m15- 6.25 m20 - 6.8 m25 - 7.5 m30- 8.5 m35- 9 m40 - 10
Cement is not used for plastering, plaster is used for this.
M 15 grade - 1:2:4Cement bags required - 6.5 bagsCement required - 325 kgs
Mix ratio for M5 concrete is 1:1.5:3compressive strength is 20N/mm2 @ 28 days.1 part of cement, 1.5 part of sand, 3 parts of coarse aggregate.
M20 - 6.20bags
315 Kg/M3 approx.
1 bag
1 bag
concrete and cement
In M20 grade concrete, the mix ratio is typically 1:1.5:3 (cement: sand: aggregates). For one cubic meter of concrete, you generally need about 7 to 8 bags of cement, as one bag of cement is approximately 50 kg. This equates to roughly 350 kg of cement per cubic meter, which aligns with the M20 mix design requirements.
1:1.5:3 (cement,stone,sand)
Yes. OPC 43 grade cement can be used to make M20 grade concrete.It can be used to make concrete up to M30 Grade.See related link.
260 kg/cu m
The mean grade of M20 concrete is defined by its compressive strength of 20 MPa (megapascals) at 28 days. This grade typically consists of a mix ratio of 1 part cement, 1.5 parts sand, and 3 parts coarse aggregate by volume. M20 concrete is commonly used for structural applications where moderate strength is required, such as in beams, slabs, and columns.
Required slump height of M20 for different concrete structures, are normally calculated by the required slump value, which would come out to be 100 lits.
quantity of cement for M20 in one cubic metercement=1440 kg/m3sand=1700 kg/m3aggregate= 1600 kg/m3Lets solve for M20 i.e, 1:1.5:31 bag of cement = 50 kg =34.7 litres=35 litresi.e, 0.035 m3(item) (w/c ratio)(water) (cement)(sand)(aggregate)volume(0.42)(21ltr)(0.035)(0.0525)(0.105)voids - (0) (0) (0 60%) (40%) (45%)solidvolume (-) (0.021) (0.014) (0.0315) (0.05775) *sum=0.124Thus 50 kg of cement gives 0.124 m3 of concrete for M20 at 0.42 w/c ratio.Hence,cement required =0.035/0.124 =0.28 m3 i.e, 0.28*1440=403kgsand required= 0.0525/0.124 =0.42 m3 i.e, 0.42*1700 = 714 kgsimilarly aggregate required = 1360 kgwater required = 169 litreCheck: 403+714+1360 = 2477 i.e, density of concrete =2477kg/m3*NOTE: The quantity of cement, sand, aggregate & water varies with the w/c ratio and the density of materials.