ketchup - the vinegar ( acetic acid ) in ketchup changes the copper oxide to copper acetate which is soluable in water.
Copper oxidation is endothermic.
The oxidation state of the cupric ion in copper tartarate is +2. Copper (II) ion, or cupric ion, has an oxidation state of +2 due to the loss of 2 electrons. In the case of copper tartarate, the ligand (tartarate) does not affect the oxidation state of the central copper ion.
It depends on the compound. +1 and +2 are the more common ones (as in Cu2I2 and CuI2 respectively). In elemental form, its oxidation number is zero.
It is not possible to reverse engineer copper. Copper is a basic element.
If the question is Cu2, then it is equivalent to Cu and the oxidation number for any element is zero. If the question is Cu2+, then the oxidation number is +2.
CuCl is copper (I) chloride, where copper has a +1 oxidation state. Cu2Cl2 is copper (II) chloride, where copper has a +2 oxidation state. The difference lies in the oxidation state of copper present in the compounds.
+2 oxidation state for the Copper. -1 for the Chloride
The common oxidation states for copper are +1 and +2. However, copper can exhibit other oxidation states such as +3 and even +4 in some rare cases.
Copper iodide has a chemical formula of CuI. In this compound, the oxidation number of copper is +1.
The formula for copper(I) chloride is CuCl, where copper has a +1 oxidation state. The formula for copper(II) chloride is CuCl2, where copper has a +2 oxidation state.
The oxidation number of copper in CuNH3Cl2NO3 is +1. This is because the overall charge of the complex ion is -1, and the oxidation numbers of N, H, Cl, and O remain the same as their typical values, leaving copper with a +1 oxidation state to balance the charge.
No, the oxidation of copper is not exothermic. It is an endothermic process, meaning it absorbs heat from its surroundings as it occurs.